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Softa [21]
3 years ago
9

How many moles of methane (CH4) could be made from 4.6 moles of hydrogen?

Chemistry
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

Number of moles of methane form = 2.3 mol

Explanation:

Given data:

Number of moles of Hydrogen = 4.6 mol

Number of moles of methane form = ?

Solution:

Chemical equation:

C + 2H₂     →   CH₄

Now we will compare the moles of methane with hydrogen from balance chemical equation.

                     H₂              :           CH₄

                       2              :             1

                     4.6             :            1/2×4.6 = 2.3 mol  

Form 3.6 moles of hydrogen 2.3 moles of methane can be formed.

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Answer:

Explanation:

Molar mass of sodium hydroxide is = 100

any compund with its molar mass dissovled in 1L itres solution gives rise to 1M solution

40 g ------> 1L ---->1M

Xg  ------>1L------>2M

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3 years ago
A sodium atom has 11 protons, 10 electrons, and 12 neutrons. What is its charge
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Answer:

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A chemical reaction in which two or more substances undergo a chemical union to form a more complex substance is a _______ react
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Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each
Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

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In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

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In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

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Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

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3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

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