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Oksi-84 [34.3K]
2 years ago
5

What are nucleotides, genes and genomes?

Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
6 0

Answer:

nucleotides=    DNA, A complex molecule that stores information using four basic coding parts, which are called nucleotides.

genes=  Chromosome A collection of genes in a long, single strand of DNA.

genomes= Genomes All the DNA that makes up the complete genetic instruction manual for humans and other organisms.<u><em> </em></u>

<h3><u><em> </em></u></h3><h3><u><em></em></u></h3>

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How to find percentage abundanace
Ghella [55]

Answer and Explanation:

How to Calculate the Percent Abundance of an Isotope

Step 1: Find the Average Atomic Mass. Identify the atomic mass of the element from your isotopic abundance problem on the periodic table. ...

Step 2: Set Up the Relative Abundance Problem. ...

Step 3: Solve for x to Get the Relative Abundance of the Unknown Isotope. ...        

 Step 4: Find percent abundance.

5 0
3 years ago
What is the definition of a Lewis acid?
Vedmedyk [2.9K]

Answer:

Explanation:

Un ácido de Lewis es una especie química que contiene un orbital vacío que es capaz de aceptar un par de electrones de una base de Lewis para formar un aducto de Lewis

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2 years ago
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Answer:

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3 years ago
Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

4 0
2 years ago
What’s the difference between an ester and an amide
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