The reaction for the combustion of methane can be expressed as follows.
CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
moles of CO2 = (5.6 L) / (22.4 L/1 mole)
moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
= 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane.

5 0

3 years ago

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You have recovered two LacZ-minus AmpR colonies from your transformation in Lab 7 and they appear as white colonies on a LBAX pl

svlad2 [7]

Answer:

D. pUC-chloramphenicol(minus)

Explanation:

It contains chloramphenicol resistance gen, the PMB1 posses origin of replication (ori), beta-galactosidase coding gen Laz. It also has pUC18 with many cloning site in the Lac Z gene which makes the recombinant clones to be verified via culture plates which is made up of IPTG and X- Gal.

7 0

3 years ago

When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be

Bas_tet [7]

Explanation:

The given precipitation reaction will be as follows.

$AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)$