Answer:
Octasulfur is just S8. Eight S atoms in
a sort of crown shape. Sulfur Dioxide is a gas, SO2. Does that help?
Explanation:
When 0.514 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.8 C to 29.4 C. Find ⌂E rxn for the combustion of biphenyl in kJ/mol biphenyl. The heat capacity of the bomb calorimeter, determined in a separate experiment, is 5.86 kJ/ C.
<span>The answer is - 6.30 * 10^3 kJ/mol
</span>
There are 13 atoms in the product
<h3>Further explanation</h3>
Given
Reaction
H2SO4 + 2KOH --> K2SO4 + 2H2O
Required
The number of atoms
Solution
In a chemical equation, there are reactants on the left and products on the right
Reactants : H2SO4 + 2KOH
Products : K2SO4 + 2H2O
The number of atoms is determined by their reaction coefficient and the subscript of the atoms in the compound
K2SO4 (coefficient = 1) :
K = 2 atoms
S = 1 atom
O = 4 atoms
Total atoms = 7 atoms
2H2O(coefficient = 2) :
H = 2 x 2 = 4 atoms
O = 2 x 1 = 2 atoms
Total atoms = 6 atoms
Total = 13 atoms
Using IMA is used in Engineering, but there is a simple rhyme I use called IMA Deer. IMA=De/Dr
Answer:
The base must be ethylamine.
Explanation:
The pH of solution of a weak base gives us an idea about the Kb of the base.
![pOH=-log[OH^{-}]](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E%7B-%7D%5D)
![[OH^{-}]=0.0062M](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%3D0.0062M)
The relation between Kb and hydroxide ion concentration is:
![Kb=\frac{[OH^{-}]^{2}}{[base]}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BOH%5E%7B-%7D%5D%5E%7B2%7D%7D%7B%5Bbase%5D%7D)
Thus the weak base must be ethylamine.
