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Dovator [93]
3 years ago
10

how much energy is required to turn 20 gram cube of ice at a temperature of -10 degrees Celsius into liquid water at a temperatu

re of 10 degrees Celsius
Physics
1 answer:
Ainat [17]3 years ago
8 0

Given that:

Mass (m) = 20 g = 0.02 Kg,

temperature (T₁) = -10°C = -10+273 = 263 K

temperature (T₂) = 10°C = 10+273 = 283 K

Specific heat of water (Cp) = 4.187 KJ/Kg k

We know that Heat transfer (Q) = m. Cp.( T₂ - T₁)

                                                    = 0.02 × 4.187 × (283-263)

                                               <em>  Q = 1.67 KJ</em>

<em>Heat transferred is 1.67 KJ</em>

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