Answer:
Explanation:
Change in velocity considering the x component will be
Final velocity-Initial velocity
Change in velocity considering the y component will be
Final velocity-Initial velocity
Resultant change in velocity
Acceleration= change in velocity per unit time hence
Answer:
a) we know that resistance is directly proportional to the length of the conductor as length increases the resistance also increases so to direct the current with least resistance, then the direction is perpendicular to side B only other sides have a larger length than B.
b) = 4.35 × 10⁻⁴ m/s
time = 229.56 s
Explanation:
Given:
a) we know that resistance is directly proportional to the length of the conductor as length increases the resistance also increases so to direct the current with least resistance, then the direction is perpendicular to side B only other sides have a larger length than B.
Dimension = 0.2m × 0.1m × 0.02m
ρ = 1.69×10⁻⁸ Ωm
= 8.49 × 10²⁸ e−/m³
Potential difference across the solid = 0.001 V
Now,
from Ohm's law V = I × R
here
V is potential difference
I is the current
R is the resistance
or
R =
also,
R =
Here, l is the length
A is the area
and,
the drift speed, =
substituting value of I in the above equation, we get
=
on substituting the values, we get
or
= 4.35 × 10⁻⁴ m/s
also,
the time taken, t =
=
= 229.56 s
Answer:
A longitudinal wave is a wave where the displacement of the medium is in the same direction than the propagation of the wave.
This means that as a P wave travels through the Earth, the relative motion between the p wave and the particles is near zero, as the motion of the particles is parallel to the motion of the wave.
An example of this would be the waves generated when you throw a rock in water, you can see how the water particles move along the waves in the water.
Answer:
Explanation:
The dart will go forward horizontally with velocity of 19 m/s. It will also fall downwards with initial velocity of zero and gravitational acceleration of 9.8 m/s².
Distance PQ covered by the dart can be calculated using the following formula.
s = ut + 1/2 at²
u is initial velocity , a is acceleration and t is time.
Putting the values
s = 0 + 1/2 x 9.8 x .19²
= .1769 m
= 17.69 cm.
Explanation:
Given that,
An ideal horizontal spring-mass system oscillates with a period of 0.60 seconds.
Mass is 3 kg but the spring constant is not known. We need to find the frequency of oscillations when this same spring and mass are arranged to hang vertically. We know that the relation between frequency and time period is inverse. Frequency is given by :
Hence, the correct option is (d) "none of the above".