1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
JulijaS [17]
3 years ago
8

Calcutale Grxn for the following equation at 25°C: 4KClO3(s) → 3KClO4(s) KCl(s)

Chemistry
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

-133.2 kJ

Explanation:

Let's consider the following balanced equation.

4 KClO₃(s) → 3 KClO₄(s) + KCl(s)

We can calculate the standard Gibbs free energy of the reaction (ΔG°rxn) using the following expression.

ΔG°rxn = 3 mol × ΔG°f(KClO₄(s)) + 1 mol × ΔG°f(KCl(s)) - 4 mol × ΔG°f(KClO₃(s))

ΔG°rxn = 3 mol × (-303.1 kJ/mol) + 1 mol × (-409.1 kJ/mol) - 4 mol × (-296.3 kJ/mol)

ΔG°rxn = -133.2 kJ

You might be interested in
Assuming that the bath contains 250.0 g of water and that the calorimeter itself absorbs a negligible amount of heat, calculate
Anvisha [2.4K]

Answer:

-3272     kJ/mol

Explanation:

Given and known facts

Mass of Benzene = 0.187 grams

Mass of water = 250 grams

Standard heat capacity of water = 4.18 J/g∙°C

Change in temperature ΔT = 7.48°C

Heat

=250 * 4.18 * 7.48\\=7816.6 \\=7.82

Heat released by benzine is - 7.82 kJ

Now, we know that

0.187 grams of benzene release = -7.82  kJ heat

So, 1 g benzine releases

\frac{ -7.82 }{0.187}\\= -41.8

kJ/g

0.187 * \frac{1}{78.108}=0.00239 mol C6H6

Heat released

= \frac{-7.82}{ 0.00239}

=-3272     kJ/mol

4 0
3 years ago
Calculate the percent dissociation of trimethylacetic acid in a aqueous solution of the stuff. You may find some useful data in
LuckyWell [14K]

Answer:

percentage dissociation of trimethylacetic acid in a 0.57M  aqueous solution = 0.40%

Explanation:

check attachment below for more information o the answer.

3 0
3 years ago
Predict and Balance the following reaction:
Umnica [9.8K]

A. The balanced chemical reaction of Sodium metal and Water is 2Na  +  2H₂O  →  2NaOH    +   H₂.

<h3>What is a balanced chemical equation? </h3>

A balanced equation contains the same number of each type of atoms on both the left and right sides of the reaction arrow.

<h3>Reaction of Sodium metal and Water</h3>

Sodium metal reacts rapidly with water to form a colourless solution of sodium hydroxide (NaOH) and hydrogen gas (H2).

The balanced chemical reaction is written below;

2Na  +  2H₂O  →  2NaOH    +   H₂

Thus, the balanced chemical reaction of Sodium metal and Water is 2Na  +  2H₂O  →  2NaOH    +   H₂.

Learn more about chemical reaction here: brainly.com/question/11231920

#SPJ1

8 0
1 year ago
What is the poH of a<br> 4.8 x 10-10 M H+ solution?
stiks02 [169]

Answer: pOH = 4.68

Explanation:

pOH = 14 - pH

pH = - Log [H+]

= - Log [4.8 x 10^-10]

= -(-9.32)

pH =+9.32

Therefore, pOH= 14 - 9.32

= 4.68

6 0
3 years ago
Convert 3.2 ft^2 to square inches
tangare [24]

460.8 square inches

3.2 * 144 = 460.8

6 0
3 years ago
Other questions:
  • Copper has an atomic number of 29 and a mass number of 64. what would result if an uncharged copper atom lost two electrons?
    8·2 answers
  • How many kilojouls are required at 0c to melt an ice cube with a mass of 25g
    13·1 answer
  • How many atoms are in 0.075 mol of titanium?
    11·2 answers
  • Which term is same for one mole of oxygen gas and one mole of water
    12·1 answer
  • What electron transition represents a gain of energy?
    14·1 answer
  • Why would a doctor most likely restrict a patient’s contact with other people while the patient receives internal radiation?
    13·2 answers
  • ________ and ________ fibres are obtained from animals ​
    11·2 answers
  • If a rock had a mass of 20g explain how you would fund the density
    15·2 answers
  • How many grams of aluminum is required to react with 75.0 ml of 2.50 M HCl?
    8·1 answer
  • 2B + 3H2 2BH3<br> How many moles of BH3 are synthesized when 27.0 moles of H2 completely react?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!