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JulijaS [17]
3 years ago
8

Calcutale Grxn for the following equation at 25°C: 4KClO3(s) → 3KClO4(s) KCl(s)

Chemistry
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

-133.2 kJ

Explanation:

Let's consider the following balanced equation.

4 KClO₃(s) → 3 KClO₄(s) + KCl(s)

We can calculate the standard Gibbs free energy of the reaction (ΔG°rxn) using the following expression.

ΔG°rxn = 3 mol × ΔG°f(KClO₄(s)) + 1 mol × ΔG°f(KCl(s)) - 4 mol × ΔG°f(KClO₃(s))

ΔG°rxn = 3 mol × (-303.1 kJ/mol) + 1 mol × (-409.1 kJ/mol) - 4 mol × (-296.3 kJ/mol)

ΔG°rxn = -133.2 kJ

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Answer:

The expression to calculate the mass of the reactant is m = \frac{1.080kJ}{31.2kJ/g}

Explanation:

<em>The amount of heat released is equal to the amount of heat released per gram of reactant times the mass of the reactant.</em> To keep to coherence between units we need to transform 1,080 J to kJ. We do so with proportions:

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A sleeping 68 kg man has a metabolic power of 65 w . you may want to review ( pages 323 - 327) . part a how many calories does h
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<u>Given:</u>

Mass = 68 kg

Power = 65 W

<u>To determine:</u>

Calories burned during an 8.0 hr sleep

<u>Explanation:</u>

Energy is expressed as:

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Now, the unit of power = Watt (W)

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Energy = 65 J/s * 28800 s = 1872000 J

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