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3 years ago

Identify earths lithospheric plates

Chemistry

1 answer:

kolezko [41]3 years ago

8 0

Answer:

Lithospheric plates are regions of Earth's crust and upper mantle that are fractured into plates that move across a deeper plasticine mantle. Earth's crust is fractured into 13 major and approximately 20 total lithospheric plates.

Explanation:

<em>I hope this helps</em>

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Section Review<br> 22<br> 1. What is meant by the term continuous spectrum?

just olya [345]

A set of attainable values for some physical quantity such as energy or wavelength

5 0

3 years ago

What is the net ionic equation for 2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 6NaOH

tatuchka [14]

Answer:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

Explanation:

First of all, let us balance the equation to give;

2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 3NaOH

Now, we can observe the presence of positive Sodium ions (Na+) and negative hydroxyl ions (OH-) on both left and right sides of the equation.

Now, the two ions will cancel out. These ions are not really involved in the overall reaction and thus do not require being written in the overall equation. Hence, the overall net ionic reaction can now be written as:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

6 0

3 years ago

What is largest value for the third quantum number

Kryger [21]

Answer:

18.

Explanation:

3s^2 3p^6 d^10

4 0

2 years ago

If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?

Cerrena [4.2K]

Answer: The concentration of $H^{+}$ ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

$pH = - log [H^{+}]$

Substitute the value into above expression as follows.

$pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M$

Thus, we can conclude that the concentration of $H^{+}$ ions in vinegar is 0.001 M.

5 0

2 years ago

If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol

igomit [66]

Answer:

$\Delta _RH=4x10^{-3}\frac{kJ}{mol}$

Explanation:

Hello,

In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

$\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}$

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

$\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}$

Best regards.

5 0

3 years ago