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2 years ago

What really is the Ebola virus?

1 answer:

7 0

The Ebola virus belongs to a family of viruses termed Filoviridae. Filovirus particles form long sometimes branched filaments of varying shapes, as well as shorter filaments , and may measure up to 14,000 nanometers in length with diameter of 80 nanometers. Viral particles contain one molecule of single stranded RNA enveloped in a lipid membrane. New viral particle bud from the surface of their host cell. Although Ebola virus was only discovered in 1976, it is an ancient virus and is thought to have split from other viruses thousands of years ago.

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45.8 g of NaCl is dissolved in 500. mL of a water (d = 1.00 g/mL) and is placed in the freezer at -1 °C overnight. Which stateme

mel-nik [20]

Answer:

i honestly don't know.

Explanation:

4 0

3 years ago

To what volume (in mL) would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN?

CaHeK987 [17]

Answer:

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN

Explanation:

Dilution is the reduction of the concentration of a chemical in a solution and consists simply of adding more solvent.

In a dilution the amount of solute does not vary. But as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a solution it is fulfilled:

Ci* Vi = Cf* Vf

where:

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

In this case:

Ci= 1.40 M
Vi= 20 mL
Cf= 0.088 M
Vf= ?

Replacing:

1.40 M* 20 mL= 0.088 M* Vf

Solving:

$Vf=\frac{1.40 M* 20 mL}{0.088 M}$

Vf= 318.18 mL

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN

7 0

2 years ago

What’s at the end of the leg bones?

Akimi4 [234]

Answer:

Calfs

Explanation:

6 0

2 years ago

The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins

saul85 [17]

The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. $(1/2)^{n} = x$ ,
where:
n - a number of half-lives
x - a remained fraction of a sample

2. $t_{1/2} = \frac{t}{n}$
where:
 $t_{1/2}$ - half-life
t - total time elapsed
n - a number of half-lives

So, we know:
t = 10 min
 $t_{1/2}$ = 2.5 min

We need:
n = ?
x = ?

We could first use the second equation to calculate n:
If:
$t_{1/2} = \frac{t}{n}$ ,
Then:
$n = \frac{t}{ t_{1/2} }$
⇒ $n = \frac{10 min}{2.5 min}$
⇒ $n=4$ 

Now we can use the first equation to calculate the remained fraction of the sample.
 $(1/2)^{n} = x$
⇒ $x=(1/2)^4$
⇒ $x= \frac{1}{16}$

3 0

2 years ago

In a reaction, a + b + c→ d, it is found that the reaction is first order in terms of a and second order in terms of b and half

Vikentia [17]

Rate=[a]*([b]^2)*([c]^(1/2)]
rate=[2a]*([b]^2)*([2c]^(1/2)]= 2*(2^(1/2)[a]*([b]^2)*([c]
it increases times 2*(2^(1/2)=2√2

6 0

2 years ago