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sukhopar [10]
3 years ago
15

The second reaction in the formation of sulfuric acid occurs slowly. no2 is added to the reaction to speed it up. in which form

would this substance be a homogeneous catalyst for this reaction? no2(g) no2(l) no2(s) no2(aq)
Chemistry
2 answers:
lozanna [386]3 years ago
6 0
I think the answer is NO2(g) :)
pochemuha3 years ago
3 0
<h2>Answer</h2>

NO2 (g)

<h3>Explanation</h3><h3>Homogeneous catalyst</h3>

If the catalyst and the reactants are in same phase, the catalysis is called homogeneous catalysis and the catalyst is called a homogeneous catalyst.

H2SO4 is usually synthesized by Contact process

The 1st step of contact process involves the reaction of sulfur and oxygen to produce sulfur dioxide.

In 2nd step sulfur dioxide is converted into sulfur trioxide by reacting it with O2 in the presence vanadium pentaoxide. We can see that both the reactants are in gaseous form so we use N02 in gaseous form.

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Identify the atoms that are oxidized and reduced, the change in the oxidation state for each, and oxidising and reducing agents
KATRIN_1 [288]

Answer:

Explanation:

a) Mg + NiCl_2 \rightarrow MgCl_2 + Ni

Oxidation state of Mg changes to 0 to +2.

Oxidation state of Ni changes to +2 to 0.

Oxidation state of Cl does not change.

So, Mg is oxidized, Ni is reduced.

Mg acts as reducing agent and NiCl_2 acts as oxidizing agent.

b) PCl_3 + Cl_2 \rightarrow PCl_5

Oxidation state of P changes to +3 to +5.

Oxidation state of Cl changes to 0 to -1.

So,

P is oxidized and Cl is reduced.

PCl_3 acts as reducing agent and Cl_2 acts as oxidizing agent.

c) C_2H_4 + 3O_2 \rightarrow 2CO_2 + 2H_2O

Oxidation state of C changes to -2 to +4.

Oxidation state of O changes to 0 to -2.

Oxidation state of H does not change.

So,

C is oxidized and O is reduced.

C_2H_4 acts as reducing agent and O_2 acts as oxidizing agent.

d) Zn + H_2SO_4 \rightarrow ZnSO_4 + H_2

Oxidation state of Zn changes to 0 to +2.

Oxidation state of H changes to +1 to 0.

Oxidation state of S and O do not change.

So, Zn is oxidized, H is reduced.

Zn acts as reducing agent and H_2SO_4 acts as oxidizing agent

e) K_2S_2O_3 + I_2 \rightarrow K_2S_4_O6 + 2KI

Oxidation state of S changes to +2 to +2.5.

Oxidation state of I changes to 0 to -1.

Oxidation state of K and O do not change.

So, S is oxidized, I is reduced.

K_2S_2O_3 acts as reducing agent and I_2 acts as oxidizing agent.

f) 3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 4H_2O+2NO

Oxidation state of Cu changes to 0 to +2.

Oxidation state of N changes to N +5 to +2.

Oxidation state of H and O do not change.

So, Cu is oxidized, N is reduced.

Cu acts as reducing agent and HNO_3 acts as oxidizing agent

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3 years ago
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Oxana [17]
Prominent copper sulfide minerals include Cu2S (chalcocite) and CuS (covellite).
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3 years ago
Compute 214.056 + 9.3456. Round the answer appropriately
shusha [124]
214.0560
+ 9.3456
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3 years ago
Oxygen is a __________ and nitrogen is a __________. metalloid, metalloid nonmetal, metal nonmetal, nonmetal nonmetal, metalloid
Anna35 [415]

Answer:

"nonmetal, nonmetal"

Explanation:

Oxygen is a non metal and Nitrogen is a non metal. It is 8th element of the periodic table. It is located in period 2 and group 16.

Nitrogen lies at the group 15 of the periodic table. Its atomic no is 7. Its valency is 2.

Hence, the correct option is (c) "nonmetal, nonmetal".

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What relationship exists between an enzyme and a catalyst?
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