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sukhopar [10]
3 years ago
15

The second reaction in the formation of sulfuric acid occurs slowly. no2 is added to the reaction to speed it up. in which form

would this substance be a homogeneous catalyst for this reaction? no2(g) no2(l) no2(s) no2(aq)
Chemistry
2 answers:
lozanna [386]3 years ago
6 0
I think the answer is NO2(g) :)
pochemuha3 years ago
3 0
<h2>Answer</h2>

NO2 (g)

<h3>Explanation</h3><h3>Homogeneous catalyst</h3>

If the catalyst and the reactants are in same phase, the catalysis is called homogeneous catalysis and the catalyst is called a homogeneous catalyst.

H2SO4 is usually synthesized by Contact process

The 1st step of contact process involves the reaction of sulfur and oxygen to produce sulfur dioxide.

In 2nd step sulfur dioxide is converted into sulfur trioxide by reacting it with O2 in the presence vanadium pentaoxide. We can see that both the reactants are in gaseous form so we use N02 in gaseous form.

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Using ideal gas equation,

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So using ideal gas equation,

n=PV/RT

=199*4.67/8.321*303\

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A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely
Rzqust [24]

Answer:

1.59 atm

Explanation:

The reaction is:

N_{2}O_{3}(g) - - -> NO_{2}(g)+NO(g)

The dalton's law tell us that the total pressure of a mixture of gases is the sum of the partial pressure of every gas.

So after the reaction the total pressure is:

P_{total}=P_{NO_{2}}+P_{NO}

we don't include N_{2}O_{3} because it decomposed completely.

Assuming  ideal gases

PV=nRT

P= pressure, V= volume of the container, n= mol of gas, R=constant of gases and T=temperature.

so moles of N_{2}O_{3} is:

n_{N_{2}O_{3}}=\frac{P_{1}V}{RT_{1}}

from the  reaction stoichiometry (1:1) we have that after the reaction the number of moles of each product is the same number of moles of N_{2}O_{3}.

n_{NO_{2}}=\frac{P_{1}V}{RT_{1}}

n_{NO}=\frac{P_{1}V}{RT_{1}}

The partial pressure of each gas is:

P_{NO_{2}}=\frac{n_{NO_{2}*R*T_{2}}}{V}

P_{NO}=\frac{n_{NO}*R*T_{2}}{V}

so total pressure is:

P_{total}=(n_{NO_{2}}+n_{NO})*\frac{R*T_{2}}{V}

replacing the moles we get:

P_{total}=(2*\frac{P_{1}V}{RT_{1}})*\frac{R*T_{2}}{V}

We know that T2=3*T1

replacing this value in the equation we get:

P_{total}=2*\frac{P_{1}V}{RT_{1}}*\frac{R*3T_{1}}{V}

P_{total}=6*P_{1} = 6*0.265 atm = 1.59 atm

5 0
3 years ago
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