Answer:
There are 3 steps of this problem.
Explanation:
Step 1.
Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.
Step 2.
Enthalpy of saturated liquid Haq = 781.124 J/g
Enthalpy of saturated vapour Hvap = 2779.7 J/g
Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g
Step 3.
In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy
So, H1=H2
H2= (1-x)Haq+XHvap.........1
Putting the values in 1
2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}
= 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)
1904.976 (J/g) = x1998.576 (J/g)
x = 1904.976 (J/g)/1998.576 (J/g)
x = 0.953
So, the quality of the wet steam is 0.953
According to sources, the most probable answer to this query is the reaction is spontaneous and will proceed without any energy input. This means that energy was produced and can result to a reaction.We appreciate your questions. Please, never hesitate to ask more in Brainly your queries.
The most appropriate answer is C !! Cs is most electropositive and thus least electronegative !!
<span>Add 3 x 10^9 +5.3 x 10^10
</span><span> 3 x 10^9
+5.3 x 10^10
</span>------------------
5.6 x 10^10
Answer:
Avogadro's Law
Explanation:
The amount of moles is directly proportional to the volume of the gas under constant temperature and pressure. That is the statement of Avogadro's law. The equation is:
V1n2 = V2n1
<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas</em>
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That means, right option is:
<h3>Avogadro's Law
</h3>
