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3 years ago

11. Many metals are described as ductile, which means they can be

Chemistry

1 answer:

lbvjy [14]3 years ago

5 0

Answer:

Option (3)

Explanation:

Ductility of a substance is defined as the property by which a substance can be hammered and change its form into thin, stretched wires. In simple words, the ductile materials can be drawn into thin wires. Some of the examples of ductile substances are gold, copper and silver.

The rocks also have this property which means that they have the capacity to get deformed into enormous strains in the absence of large scale fracturing.

Thus, the correct answer is an option (3).

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Forces that act between two molecules are referred to as intermolecular forces true or false

julsineya [31]

Answer:
TRUE: <span>Forces that act between two molecules are referred to as Intermolecular Forces.

Explanation:
Those forces which are present within the molecule among atoms are called as Intramolecular Forces, while, The forces which are present between two molecules are called as Intermolecular Forces. Intermolecular Forces are as follow,

1) Hydrogen Bond Interactions

2) Dipole-Dipole Interactions

3) London Dispersion Forces</span>

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3 years ago

Fast slow , mixed ?

Elza [17]

Answer:

Explanation:

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2 years ago

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Why is the cell a basic unit of life?

Tju [1.3M]

Answer:

Cells make up the smallest level of a living organism such as yourself and other living things. The cellular level of an organism is where the metabolic processes occur that keep the organism alive. That is why the cell is called the fundamental unit of life.

Explanation:

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2 years ago

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5Br−+BrO3−+6H+→3Br2+3H2O

sashaice [31]

Explanation :

The balanced chemical reaction is,

$5Br^-+BrO_3^-+6H^+\rightarrow 3Br_2+3H_2O$

The expression for the rates of consumption of the reactants are:

The rate of consumption of $Br^-$ = $-\frac{1}{5}\frac{d[Br^-]}{dt}$

The rate of consumption of $BrO_3^-$ = $-\frac{d[BrO_3^-]}{dt}$

The rate of consumption of $H^+$ = $\frac{1}{6}\frac{d[H^+]}{dt}$

The expression for the rates of formation of the products are:

The rate of consumption of $Br_2$ = $+\frac{1}{3}\frac{d[Br_2]}{dt}$

The rate of consumption of $H_2O$ = $+\frac{1}{3}\frac{d[H_2O]}{dt}$

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3 years ago

Metal rings can be coated with a layer of copper using electricity.

Eduardwww [97]

<u>First of all, what is electrolysis?</u>

Electrolysis is the process of breaking down ionic substances using direct current.

<u>Important points about electrolysis </u>

→ Ionic substances contain particles called ions.

→ Electricity is the flow of electrons or ions. For electrolysis to work, the compound must contain ions. The ions must be free to move for electrolysis to occur and it can happen by melting or dissolving an ionic substance in water.

→ Positively charged ions move to the negative electrode. They receive electrons and are <em>reduced</em>. The positive ions move towards the negative electrode because they want to cancel each other out.

→ Negatively charged ions move to the positive electrode. They lose electrons and are <em>oxidised</em>. The substance that is broken down is called the electrolyte <em>(an electrolyte is just a liquid or solution that can conduct electricity)</em> . The negative ions move towards the positive electrode because they want to cancel each other out.

<h3>Cathode = Negative electrode</h3><h3>Anode = Positive electrode</h3>

Metal ions form at the cathode and non-metal ions form at the anode

How I remember if an element is <em>oxidised</em> or <em>reduced</em> is by remembering OIL RIG

OIL = Oxidation is Loss (of electrons)

RIG = Reduction is Gain (of electrons)

<h2><em><u>The answer to your question</u></em></h2>

1) The first step would be to clean the metal ring and sand it down because when the metal atoms from the electrolyte are deposited onto the ring, they will form a weak bond and they may simply 'fall' off. Also this could affect conductivity and the whole experiment. The more things you do accurately now, the more accurate your result will be.

2) You want to put the solution you are given in to the tank your going to be using.

3) This is basically the main part, you want to set up the circuit, I have attached a diagram at the bottom to show you the circuit. The copper rod will be the anode and the metal ring will be a cathode (ignore the elements).

4) Now turn on the circuit and you will start to see the solution spilt with the the solution now being split some going to the anode and some going the cathode.

5) Then a thin layer should form on the electrode.

Hope this helps :)

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3 years ago