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kherson [118]
3 years ago
13

Calculate the volume in milliliters of a 5.55-g sample of a solid with a density of 3.03 g/mL

Chemistry
1 answer:
Marina86 [1]3 years ago
8 0

(4.99 g) / (3.65 g/mL) = 1.37 mL

The answer to your question is 1.37ml.
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Which type of bond is formed by two atoms that equally share one pair of electrons? (1 point) ionic covalent metallic un?
GenaCL600 [577]
It's B Covalent.Now I'll add more words since the thing says I need to write at least 20 characters.

 
4 0
3 years ago
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What is the pH of a solution of KOH with a hydroxide concentration of [OH⁻] = 1.10 x 10⁻⁴
olga2289 [7]

Answer:

p[H+] = 10.042

Explanation:

As we know that

pKw = pH + pOH......eq (1)

we will calculate the pH of OH- and then we will calculate the pH of H+

So p[OH-] = - log [1.10 * 10^{-4}]

Solving the right side of the equation, we get

p[OH-]

= - [-3.958]\\= 3.958

Now we know that

pKw = 14.0

Substituting the value of pOH in the above equation, we get -

14.0 = p[H+] + 3.958\\p[H+] = 14 - 3.958\\p[H+] = 10.042

3 0
3 years ago
Which of the following is soluble in water? <br>1-glycerin <br>2-sand<br>3-iron filing<br>4-oil​
sineoko [7]

Answer:

1-glycerin

Explanation:

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4 0
3 years ago
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What is the mole fraction of solute in a 3.19 m aqueous solution?
Bumek [7]
Molality= mol/ Kg

if we assume that we have 1 kg of water, we have 3.19 moles of solute. 

the formula for mole fraction --> mole fraction= mol of solule/ mol of solution

1) if we have 1 kg of water which is same as 1000 grams of water. 

2) we need to convert grams to moles using the molar mass of water 

molar mass of H₂O= (2 x 1.01) + 16.0 = 18.02 g/mol

1000 g (1 mol/ 18.02 grams)= 55.5 mol

3) mole of solution= 55.5 moles + 3.19 moles= 58.7 moles of solution

4) mole fraction= 3.19 / 58.7= 0.0543 
4 0
3 years ago
When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H
algol [13]

Answer: The empirical formula is CH_2 and molecular formula is C_4H_8

Explanation:

We are given:

Mass of CO_2 = 18.95 g

Mass of H_2O= 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =\frac{2}{18}\times 7.759=0.862g of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

Hence the empirical formula is CH_2.

The empirical weight of CH_2 = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4

The molecular formula will be=4\times CH_2=C_4H_8

6 0
3 years ago
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