Answer:
Explanation:
Using law of conservation of momentum during collision , velocity after collision can be found .
common velocity V = m v / ( m + M )
= .030 x 300 / ( .030 + 1 )
V= 8.7378 m /s
The kinetic energy of the bullet and block will be stored as elastic energy
1/2 ( M + m ) V² = 1/2 k A² where k is force constant and A is maximum compression in the spring .
( M + m ) V² = k A²
1.030 x 8.7378² = 2000 x A²
A² = .0393
A= .1982 m .
= 19.82 cm
The answer is high to low.
Answer:
3.5mm I guess
Explanation:
More professional people will give you the correct answer... this is just a try
Answer:
The total displacement of the car is 250 km.
Explanation:
Given that,
A car at a position 150 km [W] of Toronto travels to a position 400 km [W] of Toronto.
Total displacement = final position - initial position
= 400 km - 150 km
= 250 km
So, the total displacement of the car is 250 km.