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Feliz [49]
3 years ago
5

The molecule arrangement of ice, water and steam are very different. _______ has the most ordered arrangement, ______ has the ne

xt most orderly arrangement, and ___________ has the least orderly arrangement of molecules. A) ice, water, steam B) steam, water, ice C) water, steam, ice D) water, ice, steam
Physics
2 answers:
Eduardwww [97]3 years ago
6 0
The answer is A cuz in ice the molecules r packed cuz its solid.In water the molecukes r more free than the molecules in ice cuz its a liquid in steam the molecules have a huge gap between each other.
Elis [28]3 years ago
3 0

<u>Answer </u>

A) Ice, water, steam

<u>Explanation </u>

Ice is inform of a solid. Solids have particles that are tightly packed and they are in a regular pattern. For this reason they have the most ordered arrangement.

Water is a liquid. It has particles that are closely together but they are not in regular arrangement. For this reason they are next after ice.

Steam is in gaseous state. Gases have particles that are well separated with no definite arrangement. Hence they are the least in the order of molecule arrangement.




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Answer:

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F= force test line (N)

W : fish weight  (N)

Problem development

(a) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled in at constant speed

We apply Newton's first law of equlibrio because the system moves at constant speed:

∑Fy =0

F-W= 0

42N -W =0  

W = 42N

(b) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled with an acceleration whose magnitude is 1.41 m/s²

We apply Newton's second law because the system moves at constant acceleration:

 m= W/g , m= W/9.8 ,  m:fish mass , W: fish weight g:acceleration due to gravity

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We look for the components of speed with trigonometry

         sin 43 = v_{oy} / v₀

         cos 43 = v₀ₓ / v₀

         v_{oy} = v₀ sin 43

         v₀ₓ = v₀ cos 43

Let's look for time in the first equation and substitute in the second

         t = x / v₀ cos 43

         y = v₀ sin 43 (x / v₀ cos 43) - ½ g (x / v₀ cos 43)²

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We solve the second degree equation

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         t₂ = 2.04 s

The shortest time is when the cliff passes and the longest when it reaches the floor, with this time we look for the horizontal distance traveled

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