Explanation:
Below is an attachment containing the solution
Answer:
magnitude v0x = v0 * cos θ = 31 m/s * cos 16° = 30 m/s
Explanation:
Please see the figure for a graphical description of the problem. As you can see from the figure, the vector v0 (initial velocity) is the sum of its horizontal and vertical components v0x + v0y.
Using the trigonometric rule for right triangles:
cos θ = adjacent / hypotenuse
We can calculate the magnitude of the v0x vector.
Seeing the figure, notice that the vectors v0, its horizontal component, v0x, and its vertical component, v0y, form a right triangle.
v0x is the side adjacent to the angle θ, and v0 is the hypotenuse of the triangle. Then:
cos θ = magnitude v0x / magnitude v0
magnitude v0x = magnitude v0 * cos θ = 31 m/s * cos 16° = 30 m/s
ANSWER: 170 Feet
REASON: with good breaks and a dry road your car should stop and skip 170 feet, with perception and reaction time of stopping you should stop within 170 feet
Answer:
V = 346.15 Volts
Explanation:
Given that,
Diameter of the sphere, d = 0.390 cm
Radius, r = 0.195 cm
Charge,
The electric potential near its surface is given by :
So, the potential near its surface is equal to 346.15 V.
Givens:
Acceleration (a) = 32.17 ft/s² as that is the only force acting on the stone in free fall assuming no air resistance
Initial velocity (V1) = 0 ft/s as that it the starting speed of the stone as all objects about to move from rest must start at 0 velocity at rest = 0 velocity
Final velocity (V2) = 120 ft/s
Displacement aka. the
height of the cliff (Δd) = ? ft
The kinematic formula we can use is: V2² = V1² + 2(a)(Δd)
Isolate to solve for Δd and just plug in the numbers!
V2² = V1² + 2(a)(Δd)
(120)² = (0)² + 2(32.17)(Δd)
14400 = 2(32.17)(Δd)
= Δd
223.9 = Δd
Therefore, the height of the cliff is 223.9 ft! Hope this helped! :)