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EleoNora [17]
3 years ago
13

At a pressure 43 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of t

he gas is decreased to 8 liters, what is the new pressure?
Physics
1 answer:
Allisa [31]3 years ago
7 0
P = 43 * 10^3
V = 12 L

P' =?
V' = 8 L

PV = P'V'
43*10^3* 12 = P' * 8

I know you can do it from here, mate ;)
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umka2103 [35]

Oscillation is a type of periodic motion which repeats itself to and from about a point which is called mean position. The period of a Pendulum can be described as a ratio between the length and gravity as,

T = 2\pi \sqrt{\frac{L}{g}}

Here,

L = length

g = Gravity

If we rearrange  to find the length we have that,

L = \frac{T^2g}{4\pi^2}

Our period is 2s and the gravity is 9.8m/s^2, then,

L = \frac{(2)^2(9.8)}{4\pi^2}

L = 0.9929m

The simple required length of the pendulum must be 0.9929m

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4 years ago
After creating a question and forming a hypothesis, what is the next step in the scientific method
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The next step is to create research
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3 years ago
A grating has 460 rulings/mm. What is the longest wavelength for which there is a 6.0th-order diffraction line
mestny [16]

Answer:

λ = 3.62 x 10⁻⁷ m = 362 nm

Explanation:

The grating equation gives the relationship between the wavelength, the diffraction line order and the diffraction angle. The grating equation is written as follows:

mλ = d Sinθ

where,

m = order of diffraction = 6

λ = longest wavelength = ?

d = 1/(460 rulings/mm)(1000 mm /1 m) = 2.17 x 10⁻⁶ m/ruling

θ = Diffraction angle = 90° (for longest wavelength)

(6)λ = (2.17 x 10⁻⁶ m/ruling) Sin 90°

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3 0
4 years ago
A roller skater of 47kg moving with a velocity of 12 m/s to the east picks up a bag of 6.0 kg. What is the final velocity of the
WITCHER [35]

Answer:

v_f = 10.85 m/s

Explanation:

We will apply the law of conservation of momentum here:

m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f}+m_{2}v_{2f}\\

where,

m₁ = mass of roller skater = 47 kg

m₂ = mass of bag = 6 kg

v_1i = initial speed of roller skater = 12 m/s

v_2i = initial speed of the bag = 0 m/s

v_1f = final speed of the roller skater = ?

v_2f = final speed of the bag = ?

Both the bag and the skater will have same speed at the end because kater is carrying the bag:

v_1f = v_2f = v_f

Therefore, the equation will become:

(47\ kg)(12\ m/s)+(6\ kg)(0\ m/s)=(47\ kg)(v_{f})+(5\ kg)(v_{f})\\564\ N.s = (47\ kg+5\ kg)(v_{f})\\v_{f} = \frac{564\ N.s}{52\ kg}\\

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If the probes are identical, then the one that feels a larger gravitational
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3 years ago
Read 2 more answers
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