I think its nitrogen sorry if I’m wrong
Answer:
The answer to the question is
The distance d, which locates the point where the light strikes the bottom is 29.345 m from the spotlight.
Explanation:
To solve the question we note that Snell's law states that
The product of the incident index and the sine of the angle of incident is equal to the product of the refractive index and the sine of the angle of refraction
n₁sinθ₁ = n₂sinθ₂
y = 2.2 m and strikes at x = 8.5 m, therefore tanθ₁ = 2.2/8.5 = 0.259 and
θ₁ = 14.511 °
n₁ = 1.0003 = refractive index of air
n₂ = 1.33 = refractive index of water
Therefore sinθ₂ = = = 0.1885 and θ₂ = 10.86 °
Since the water depth is 4.0 m we have tanθ₂ = or x₂ = = = 20.845 m
d = x₂ + 8.5 = 20.845 m + 8.5 m = 29.345 m.
C it’s the definition of ingenious rock hope this helps god bless
The total displacement for the trip is 5510 m
<h3>
Calculation and Parameters</h3>
During part 1, the distance travelled is
(1/2) a t^2
= (1/2)(2.77)(225)
= 311.6 m
The final speed gotten is (2.77)(15)
= 41.55 m/s.
The average speed for that interval is half of that or 20.8 m/s
During part 2, the distance traveled is
41.55 m/s*2.05 min*60 sec/min
= 5110 m/s
During part 3, the speed drops from 41.55 m/s to
41.55 - (9.47)(4.39)
= 0
The average speed during this interval is
41.55/2 - 20.78 m/s
The distance travelled is 20.78*4.39
= 91.2 m/s
Total distance travelled = 312 + 5110 + 91 = 5513 m
The average speeds for legs 1,2,and 3 of the trip as well as for the complete trip are:
- 20.8 m/s,
- 41.6 m/s,
- 20.8 m/s,
- 38.7 m/s
Read more about average speed here:
brainly.com/question/6504879
#SPJ1
Explanation:
If the satellite is moving too quickly then the gravitational attraction between the Earth and the satellite is too weak to keep it in orbit. If this is the case, the satellite will move off into space. This occurs at speeds around or above 11,200 metres per second (m/s).