Answer:
The height is "89.61 m". A further explanation is given below.
Explanation:
According to the question,
Mass of rocket,
m = 5 kg
Time,
t = 4.6 s
Initial speed of rod
u = o m/s
Final speed,
v = 39 m/s
drag,
= 60 N
So,
⇒ acceleration, ![a=\frac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7D%7Bt%7D)
![=\frac{39-0}{4.6}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B39-0%7D%7B4.6%7D)
![= 8.478 \ m/s^2](https://tex.z-dn.net/?f=%3D%208.478%20%5C%20m%2Fs%5E2)
⇒ ![F_{net}= Net \ force](https://tex.z-dn.net/?f=F_%7Bnet%7D%3D%20Net%20%5C%20force)
![=ma](https://tex.z-dn.net/?f=%3Dma)
![=5\times 8.478](https://tex.z-dn.net/?f=%3D5%5Ctimes%208.478)
![=42.89 \ N](https://tex.z-dn.net/?f=%3D42.89%20%5C%20N)
Now,
The thrust will be:
⇒ ![Thrust-weight-drag=Net \ force](https://tex.z-dn.net/?f=Thrust-weight-drag%3DNet%20%5C%20force)
⇒ ![Thrust-(5\times 9.8)-60=42.89](https://tex.z-dn.net/?f=Thrust-%285%5Ctimes%209.8%29-60%3D42.89)
⇒ ![Thrust-49-60=42.89](https://tex.z-dn.net/?f=Thrust-49-60%3D42.89)
⇒ ![Thrust-109=42.89](https://tex.z-dn.net/?f=Thrust-109%3D42.89)
⇒ ![Thrust=42.89+109](https://tex.z-dn.net/?f=Thrust%3D42.89%2B109)
⇒ ![Thrust=151.89 \ N](https://tex.z-dn.net/?f=Thrust%3D151.89%20%5C%20N)
The height will be:
⇒ ![h=\frac{1}{2} at^2](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B1%7D%7B2%7D%20at%5E2)
![=\frac{1}{2}\times 8.47\times (4.6)^2](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%208.47%5Ctimes%20%284.6%29%5E2)
![=\frac{1}{2}\times 8.47\times 21.16](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%208.47%5Ctimes%2021.16)
![=89.61 \ m](https://tex.z-dn.net/?f=%3D89.61%20%5C%20m)
solution:
the pressure difference is
P2 - P1 = (F/A)
![where f is force and A=\pi \times(\frac{d^2}{4})\\=12mm=12\times10^{-3}](https://tex.z-dn.net/?f=where%20f%20is%20force%20and%20A%3D%5Cpi%20%5Ctimes%28%5Cfrac%7Bd%5E2%7D%7B4%7D%29%5C%5C%3C%2Fp%3E%3Cp%3E%3D12mm%3C%2Fp%3E%3Cp%3E%3D12%5Ctimes10%5E%7B-3%7D)
Answer:
10kg
Explanation:
(I'm not super familiar with the GRESA method so apologies for any inaccuracies)
Given: We are given values for Force: 100N, and Acceleration: 10m/s2.
Required: We are trying to find Mass (m)
Equation: The best equation to use to solve this problem is F=ma,
Force = Mass x Acceleration. We can rearrange this for mass: m = F/a.
Solution: By substituting in the values we have: ![m = \frac{100}{10}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B100%7D%7B10%7D)
Answer: Mass = 10kg
Hope this helped!
Answer: 18 MN/C
Explanation: Taking into account the weigth (m* g) and electric force for a charge in a electric fiel as (q*E) both are equals
so 0.0142 Kg*9.8 m/s^2= q*E
thus E= (0.0142*9.8)/(7.7*10^-9)