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max2010maxim [7]
3 years ago
15

What net force would be needed to accelerate the box at 2.3 m/s^2

Physics
2 answers:
Akimi4 [234]3 years ago
6 0
The pertinent equation here is F=ma.  You haven't shared the mass of the box, so I will use M to represent that mass.

Then F = M(<span>2.3 m/s^2)        (answer)</span>
Hoochie [10]3 years ago
4 0
The required force, in newtons, is

(2.3) x (the mass of the box, in kilograms) .
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Answer:

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The step by step calculation can be found in the attachment below. Thank you.

8 0
2 years ago
Which of the following statements correctly describes the index of refraction of a material? Select all that apply.
mote1985 [20]

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Option C and D only

Explanation:

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Option B is correct as the speed of light in vacuum is always greater than the speed of light in any given medium.

Option C is correct

Option D is incorrect

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2 years ago
A wheel moves in the xy plane in such a way that the location of its center is given by the equations xo = 12t3 and yo = R = 2,
Stella [2.4K]

Answer:

the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s  is   P =  104.04 \hat{i} -314.432 \hat{j}

Explanation:

The free-body  diagram below shows the interpretation of the question; from the diagram , the wheel that is rolling in a clockwise directio will have two velocities at point P;

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Now;

V_x = \frac{d}{dt}(12t^3+2) = 36 t^2

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3 years ago
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Answer:

Explanation:

We need the power equation here:

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