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3 years ago

What net force would be needed to accelerate the box at 2.3 m/s^2

2 answers:

6 0

The pertinent equation here is F=ma. You haven't shared the mass of the box, so I will use M to represent that mass.

Then F = M(2.3 m/s^2) (answer)

Hoochie [10]3 years ago

4 0

The required force, in newtons, is

(2.3) x (the mass of the box, in kilograms) .

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Natali [406]

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2 years ago

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3 years ago

Read 2 more answers

A man stands on top of a cliff and shouts.

satela [25.4K]

$\small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x$

$\small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return = \frac{2x}{v} = 1$

$\bf \to \: x = \frac{320}{2} m = 160m$

$\small \bf \: thus \: the \: distance \: between \: the \: cliffs \: = 160m \times 2 = 320m$

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2 years ago

a skinny girl devours food that is equivalent to 600 kcal, as she is anorexic she repents and wants to lose twice as many calori

blondinia [14]

Answer:

Explanation:

Work done in lifting the weight once = mgh

= 20 x 9.8 x (1.9+1.7)

= 705.6 J

= 705.6 / 4.2 calorie

= 168 cals

Total energy to be spent = 600 x 10³ cals

No of times weight is required to be lifted

= 600 x 10³ / 168

= 3.57 x 10³ times

Total time to be taken = 2 x 3.57 x 10³

= 7.14 x 10³ s

=119 minutes .

4 0

3 years ago

A particle moving in the x direction is being acted upon by a net force f(x)=cx2, for some constant

makkiz [27]

The work-energy theorem states that the change in kinetic energy of the particle is equal to the work done on the particle:
$\Delta K = W$
The work done on the particle is the integral of the force on dx:
$W= \int\limits^{3L}_L {F(x)} \, dx = \int\limits^{3L}_L {cx^2} \, dx = \frac{26}{3}cL^3$
So, this corresponds to the change in kinetic energy of the particle.

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3 years ago