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Lerok [7]
3 years ago
12

Mr. Hoffman, a science teacher, drove 10 miles to school from home in 20 minutes. He drove the 10 miles home in 30 min. His aver

age velocity was _____ m/s.
Physics
2 answers:
olga2289 [7]3 years ago
7 0
His average velocity for the day was 0. He ended where he started so his displacement was 0.
Andrews [41]3 years ago
4 0

zero.

Because he finished right where he started. his total displacement zero. therefore, his average velocity was also zero  

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Suppose a standing wave created on a spring that is 10.5 m long has a speed of 14 m/s and a frequency of 2 Hz. How many nodes an
dimulka [17.4K]

Answer:

If the two waves have the same amplitude and wavelength, then they alternate between ... In fact, the waves are in phase at any integer multiple of half of a period: ... The propagation velocity of the waves is 175 m/s.

Explanation:

please ask me in brainlist ok

6 0
3 years ago
A sound travels down a hallway that is 115 m long. Then it echoes and
yan [13]

Answer:

0.66 s

Explanation:

∆x = v∆t → 2 × 115 = 350 ∆t → ∆t = 230/350 = 0.66 s

7 0
2 years ago
You are trying to determine the specific gravity of a solid object that floats in water. If m is the mass of your object, mS is
Alisiya [41]

Answer:

Specific Gravity = m/[m(s)-m(os)]

Explanation:

Specific gravity, also called relative density, is the ratio of the density of a substance to the density of a reference substance. By this definition we need to find out the ratio of density of the object of mass m to the density of the surrounding liquid.

m = mass of the object

<u>Weight in air</u>

W (air) = mg, where g is the gravitational acceleration

<u>Weight with submerged with only one mass</u>

m(s)g + Fb = mg + m(b)g, <em>consider this to be equation 1</em>

where Fb is the buoyancy force

Weight with submerged with both masses

m(os)g + Fb’ = mg + m(b)g, <em>consider this to be equation 2</em>

<u>equation 1 – equation 2 would give us</u>

m(s)g – m(os)g = Fb’ – Fb

where Fb = D x V x g, where D is the density of the liquid the object is submerged in, g is the force of gravity and V is the submerged volume of the object

m(s)g – m(os)g = D(l) x V x g

m(s) – m(os) = D(l) x V

we know that Mass = Density x V, which in our case would be, D(b) x V, which also means

V = Mass/D(b), where D(b) is the density of the mass

<u>Substituting V into the above equation we get</u>

m(s) – m(os) = [D(l) x m)/ D(b)]

Rearranging to get the ratio of density of object to the density of liquid

D(b)/D(l) = m/[m(s)-m(os)], where D(b)/D(l) denotes the specific gravity

8 0
3 years ago
A 4-kilogram ball moving at 8 m/sec to the right collides with a 1-kilogram ball at rest. After the collision,
elena-14-01-66 [18.8K]
Conservation of momentum: total momentum before = total momentum after

Momentum = mass x velocity

So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32

Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32

Therefore β = 12.8 m/s
4 0
3 years ago
Please help me with this please <br><br> I’ll mark you Brainly
ivolga24 [154]
I think it is option (C).

If the answer is helpful then mark me as brainly.
4 0
2 years ago
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