To solve this problem we will apply Newton's second law, which indicates that the force is equivalent to the product between mass and acceleration, so

$F = ma$

Here,

F= Force

m = Mass

a = Acceleration

Rearranging to find the mass we have,

$m = \frac{F}{a}$

The value of the acceleration is

$a = 18miles/hour^2 (\frac{0.00012417m/s^2}{1 miles/hour^2})$

$a = 0.002235m/s^2$

Replacing to find the mass,

$m = \frac{53kN}{0.002235m/s^2}$

$m = \frac{53*10^{-3}}{0.002235}$

$m = 23.71kg$

Now in ponds this value is

$m = 23.71kg(\frac{2.205lb}{1kg})$

$m=52.8 lb$

Therefore the mass of the spacecraft is 52.8lb

4 0

3 years ago

The equilibrium constant for a given reaction... Group of answer choices always increases with temperature. increases with tempe

adell [148]

Explanation:In exothermic reactions, increase in temperature decreases the equilibrium constant, K, whereas, in endothermic reactions, increase in temperature increases the K

8 0

3 years ago

A rope is wrapped three and a half times around a cylinder. Determine the range of force T exerted on the free end of the rope f

Taya2010 [7]

The range of force exerted at the end of the rope is 285.7 N to 1,000 N.

<h3>Net horizontal force of the cylinder</h3>

The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.

∑F = 0

F - μFn = 0

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force increases as the number of turns of the rope increases.

minimum force = total force/number of turns of rope

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

Learn more about Newton's second law of motion here: brainly.com/question/3999427

8 0

2 years ago