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Shkiper50 [21]
3 years ago
10

What is the frequency of a wave whose wavelength is 0.7m and whose velocity is 120m/s?

Physics
1 answer:
ANEK [815]3 years ago
5 0

Answer:

f=171.43Hz

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

The frequency formula is: f=v÷λ, where <em>v</em> is the velocity and <em>λ</em> is the wavelength.

Then replacing with the data of the problem,

f=\frac{120\frac{m}{s} }{0.7m}

f=171.43\frac{1}{s}

f=171.43 Hz (because \frac{1}{s} = Hz, 1 hertz equals 1 wave passing a fixed point in 1 second).

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Brittany stands at rest on a skateboard. The combined mass of Brittany and the skateboard is 62 kg. Dave tosses a 3.7-kg pumpkin
Amiraneli [1.4K]

Answer:

3.196 m/s

Explanation:

Parameters given:

Mass of Brittany and the skateboard, M = 62 kg

Mass of pumpkin, m = 3.7 kg

Initial speed of Brittany and the skateboard, U = 0 m/s

Final velocity of Brittany, the skateboard and the pumpkin, V = v = 0.18 m/s

We can solve this problem by applying the principle of conservation of momentum.

It states that the total final momentum of a system is equal to the total initial momentum of the system.

M*U + m*u = M*V + m*v

Where u is the initial velocity of the pumpkin.

Since the final velocity of Brittany and the skateboard is equal to the final velocity of pumpkin:

M*U + m*u = (M + m) *v

Solving this to get u:

(62 * 0) + (3.7 * u) = (62 + 3.7) * 0.18

0 + 3.7u = 65.7 * 0.18

3.7u = 11.826

u = 11.826 / 3.7

u = 3.196 m/s

The initial velocity of the pumpkin was 3.196 m/s.

5 0
3 years ago
If the force vector has a magnitude of F = 12.5 N, the displacement has a length of Δr = 0.75 m, and the angle between the vecto
Thepotemich [5.8K]

Answer: 8.81 J

Explanation: The scalar or dot product of 2 vector equals the product of the magnitude of both vectors and the cosine value of the angle between them

Magnitude of vector f (force) as given in the question = 12.5N

Magnitude of length = 0.75m

Angle between vectors = 25°

F. Δr = 12.5 * 0.75 * cos 25

F. Δr = 12.5 * 0.75 * 0.9063

F. Δr = 8.81 J

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A quarterback throws a football with an initial velocity v at an angle θ above horizontal. Assume the ball leaves the quarterbac
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(a) The y-component or vertical velocity is calculated using:
Vy = Vsin(∅)

(b) The x-component or horizontal velocity is calculated using:
Vx = Vcos(∅)
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