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ANEK [815]
4 years ago
12

How would you make a structure stronger?

Physics
1 answer:
Goshia [24]4 years ago
6 0
Make the foundation more sturdy
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Define sporulation and fragmentation​
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Sporulation

the formations of spores from vegetative cells during unfavorable environmental conditions

Fragmentation

The asexual reproduction, where the body of the organism breaks into smaller pieces

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What happens in a neutralization reaction?
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<span>A neutralization reaction occurs when an acid and a base (usually both are in acqueous solutions) react to form water and a salt, which do not exhibit any of the acid or base properties. An acid is identified by being paired with a hydrogen ion and a base is identified by being paired with a hydroxide group.</span><span />
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What would be the resulting condition if Earth's axis was perpendicular to the Sun?
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I belive it would be B or D, but B seems more likely

Explanation:

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Which step is part of the information of a batholith?
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Many plutons clump together as they grow through the crust. 
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A boy reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 m above the ground as he rele
e-lub [12.9K]

MARK ME BRAINLIEST PLEASE!!!!!

The total energy TE = mgh + 1/2 mU^2; where h = 20 m, g = 9.81 m/sec^2, and U = 10 mps. When the ball reaches max height H, all that TE will be potential energy PE = mgH = TE.

So there you are. TE = mgh + 1/2 mU^2 = mgH = TE from the conservation of energy. Solve for H.

1) H = (gh + 1/2 U^2)/g = h + U^2/2g = ? meters where everything on the RHS is given. You can do the math.

2) As the ball drops from H to h, it picks up KE as the potential energy mgH is converted when the potential energy is diminished to mgh, where h < H. So PE - pe = ke = mg(H - h) = 1/2 mv^2 so solve for v = sqrt(2g(H - h)) and, again, everything is given. You can do the math.

3) Same deal as 2) except now its V = sqrt(2gH) because all the PE = mgH = 1/2 mV^2 = KE when it is about to hit the ground. You can do the math.

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