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nataly862011 [7]
4 years ago
12

Prove that relation between S.I unit of energy and commercial unit of energy

Physics
1 answer:
Oduvanchick [21]4 years ago
5 0

Relation between SI unit and Commercial Unit of energy is                                1 kWh = 3.6 × 10^6 J

<u>Explanation</u>:

  • Commercial unit of energy is kiloWatt-hour (kWh) and SI unit of energy is Joule (J).
  • 1 kiloWatt hour = 1000W × 1h

Now, 1 W = 1 J/sec

⇒ 1 kiloWatt hour = 1000 × 60 × 60 (Since 1 h = 60 × 60 s)

⇒ 1 kWh = 3.6 × 10^6 J

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A bus makes a 10-kilometer journey through town. It's top speed is 50 km/h and it's mean speed is 16kn/h. Explain why these spee
Maru [420]

Answer:

speed are different at different places

Explanation:

because it's top speed is 50km/h,so it's initial speed may be less. when it covers some distance it's speed changes again. then we have given a mean speed .mean speed means sum of all speed divided by sum of total time.so the mean speed and final speed differs from each other

6 0
3 years ago
Perception of color is determined by the wavelength of light that an object reflects
7nadin3 [17]

Answer:

True

Explanation:

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8 0
4 years ago
Can someone please help me out
tia_tia [17]

Answer:

its 0

Explanation:

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4 0
3 years ago
Read 2 more answers
3) A fahrenheit thermometer shaded from the sun on a hot day reads 101⁰ what is the temperature on the centigrade scale?
Galina-37 [17]

Answer:

38.33°C

Explanation:

Applying,

180/100 = (F-32)/C............. Equation 1

Where F = Temperature of the hot day in fehrenheit, C = Temperature of the hot day in centigrade.

make C the subject of the equation

C = 100(F-32)/180.............. Equation 2

From the question,

Given: F = 101°F

Substitute into equation 2

C = 100(101-32)/180

C = 38.33°C

3 0
3 years ago
Four waves are described by the following equations, where distances are measured in meters and times in seconds. I. y = 0.12 co
marishachu [46]

Answer:

Wave 1 and Wave 2.      

Explanation:

We know that the general equation of a wave is given by :

y=A\ sin(kx-\omega t)    

or

y=A\ cos(kx-\omega t)    

We know that the speed of a wave is given by :

v=\dfrac{\omega}{k}

Where

\omega = angular speed

k = propagation constant

Wave 1.

y=0.12\ cos(3x-21t)

v_1=\dfrac{21}{3}=7\ m/s

Wave 2.

y=0.15\ cos(6x+42t)

v_2=\dfrac{42}{6}=7\ m/s

Wave 3.

y=0.13\ cos(6x+21t)

v_3=\dfrac{21}{6}=3.5\ m/s

Wave 4.

y=-0.23\ cos(3x-42t)

v_1=\dfrac{42}{3}=14\ m/s

It is clear that wave 1 and 2 have the same speed i.e. 7 m/s. Hence, this is the required solution.

5 0
4 years ago
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