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erma4kov [3.2K]
3 years ago
12

The drawing shows a wire composed of three segments, AB, BC, and CD. There is a current of I = 2.0 A in the wire. There is also

a magnetic field B (magnitude = 0.25 T) that is the same everywhere and points in the direction of +z axis. The lengths of the wire segments are LAB = 1.0 m, LBC = 0.7 m, and LCD = 0.7 m. Find the magnitude of the force that acts on each segment.
Physics
1 answer:
alexdok [17]3 years ago
7 0

Answer:

The magnitude of the magnetic force acting on the wire is zero, because the magnetic field is parallel to the wire.

In fact, the magnetic force exerted by the magnetic field on the wire is

where I is the current in the wire, L the length of the wire, B the magnetic field intensity and  the angle between the direction of B and the wire. In our problem, B and the wire are parallel, so the angle is  and so , therefore the magnetic force is zero: F=0.

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20. Using the picture, how many neutrons does lithium have?
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Answer:

No. of Neutrons = 3

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Write an email to a classmate explaining why the velocity of the current in a river has no FN C02-F20-OP11USB effect on the time
anzhelika [568]

The velocity of the current in a river has no effect on the the time it takes to paddle a canoe across the river, given that the boat is pointed perpendicular to the bank of the river, because

The velocity of the river does not change the velocity and therefore the distance traveled in the direction of the boat which is directed perpendicular to it

Reason:

Let \overset \rightarrow {v_y} represent the velocity of the boat across the river in the direction, \overset \rightarrow {d_y}, and let, \overset \rightarrow {v_x}, represent the velocity of the river, we have;

The velocity of the boat perpendicular to the direction of the river = \overset \rightarrow {v_y}

Therefore, the distance covered per unit time in the perpendicular direction

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the perpendicular direction is the same, for every value of the velocity of

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This is so because the velocity in the perpendicular direction to the flow of

the river, which is the velocity of the boat is unchanged by the velocity of

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\overset \rightarrow {v_y} = 3 m/s

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  • The resultant velocity = \sqrt{(3 \ m/s)^2 + (4 \ m/s)^2} =5 \ m/s

The direction, θ, is given as follows;

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The length of the path of the boat, <em>l</em>, is given as follows;

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The time it takes to cross the river, t = \dfrac{l}{v}, therefore;

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distance covered in the direction of the boat is unaffected by the velocity

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Learn more vectors here:

brainly.com/question/15907242

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