The initial position of the object was found to be 134.09 m.
<u>Explanation:</u>
As displacement is the measure of difference between the final and initial points. In other words, we can say that displacement can be termed as the change in the position of the object irrespective of the path followed by the object to change the path. So
Displacement = Final position - Initial position.
As the final position is stated as -55.25 meters and the displacement is also stated as -189.34 meters. So the initial position will be
Initial position of the object = Final position-Displacement
Initial position = -55.25 m - (-189.34 m) = -55.25 m + 189.34 m = 134.09 m.
Thus, the initial position for the object having a displacement of -189.34 m is determined as 134.09 m.
Answer:
962291.57928 m²
Explanation:
= Pressure =
(full reflection)
I = Intensity = 
P = Power = 
c = Speed of light = 
M = Mass of Sun = 
m = Mass of ship = 1500 kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
Force of radiation is given by

This force will balance the gravitational force as stated in the question

The area of the must be 962291.57928 m²
According to Charles law, we know, at constant pressure, volume is directly proportional to temperature.
So, <span>V/T = constant
</span>
V₁/t₁ = V₂/t₂
V₁t₂ = V₂t₁
Here, we have: V₁ = 9 mL
V₂ = ?
T₂ = 50+272 = 323 K
T₁ = 19+273 = 292 K
Substitute their values into the expression:
9 × 323 = V₂ × 292
V₂ = 2907 / 292
V₂ = 9.95
After rounding-off to unit place value, it would be equal to 10 mL
So, In short Option C would be your correct answer.
Hope this helps!
Answer:
1) 1.31 m/s2
2) 20.92 N
3) 8.53 m/s2
4) 1.76 m/s2
5) -8.53 m/s2
Explanation:
1) As the box does not slide, the acceleration of the box (relative to ground) is the same as acceleration of the truck, which goes from 0 to 17m/s in 13 s

2)According to Newton 2nd law, the static frictional force that acting on the box (so it goes along with the truck), is the product of its mass and acceleration

3) Let g = 9.81 m/s2. The maximum static friction that can hold the box is the product of its static coefficient and the normal force.

So the maximum acceleration on the block is

4)As the box slides, it is now subjected to kinetic friction, which is

So if the acceleration of the truck it at the point where the box starts to slide, the force that acting on it must be at 136.6 N too. So the horizontal net force would be 136.6 - 108.3 = 28.25N. And the acceleration is
28.25 / 16 = 1.76 m/s2
5) Same as number 3), the maximum deceleration the truck can have without the box sliding is -8.53 m/s2