Question

The moon's gravity is one-sixth that of the earth. what is the period of a 2.00m long pendulum on the moon

Answer 1

Answer:

6.96 s

Explanation:

The period of a simple pendulum is given by:

$T=2 \pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum and g the acceleration due to gravity.

In this problem, we have a pendulum with length L = 2.00 m, while the acceleration due to gravity is 1/6 that of the earth:

$g' = \frac{g}{6}=\frac{9.8 m/s^2}{6}=1.63 m/s^2$

So, the period of the pendulum on the moon is

$T=2 \pi \sqrt{\frac{2.00 m}{1.63 m/s^2}}=6.96 s$