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2 years ago

The moon's gravity is one-sixth that of the earth. what is the period of a 2.00m long pendulum on the moon

Physics

1 answer:

erik [133]2 years ago

3 0

Answer:

6.96 s

Explanation:

The period of a simple pendulum is given by:

$T=2 \pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum and g the acceleration due to gravity.

In this problem, we have a pendulum with length L = 2.00 m, while the acceleration due to gravity is 1/6 that of the earth:

$g' = \frac{g}{6}=\frac{9.8 m/s^2}{6}=1.63 m/s^2$

So, the period of the pendulum on the moon is

$T=2 \pi \sqrt{\frac{2.00 m}{1.63 m/s^2}}=6.96 s$

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enot [183]

Answer:

The center of mass of three mass in the x-y plane is located at (1,0.5).

Explanation:

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The center of mass in y direction is :

$C_y=\dfrac{6\times 0+4\times 0+2\times 3}{6+4+2}\\\\C_y=0.5$

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2 years ago

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TiliK225 [7]

Answer:

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Explanation:

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2 years ago

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baherus [9]

Explanation:

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zepelin [54]

Answer: The cylinder

Explanation:

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Recall;

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Where ,

h= the co efficient of convective heat transfer

A= the cross sectional area.

As such, since the sphere has a smaller surface area relative to the cylinder, the sphere transfers heat slower than the cylinder.

Therefore, if the sphere and cylinder are exposed to convection in the same environment, then, the cylinder cools faster.

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baherus [9]

Answer:

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Explanation:

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2 years ago