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RSB [31]
3 years ago
14

A 1451 kg car is traveling at 48.0 km/h. Compared to 48.0 km/h, what would be the fraction of energy the car would have if it we

re traveling at 24.0 km/h.
Physics
2 answers:
Rzqust [24]3 years ago
8 0
Ke = (1/2)(m)(v^2)
Ke = (1/2)(1451kg)(48^2)
Ke = 1,671,552 joules

Ke = (1/2)(1451)(24^2)
Ke = 417,888

1/4th the energy




Marat540 [252]3 years ago
3 0
We know, kinetic energy is directly proportional to the square of velocity, So, if kinetic energy is halved it's velocity will reduce to its 1/4th value

In short, Your Answer would be 1/4

Hope this helps!
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The rates of obesity have more than doubled for children between the ages of 6 and 11 since the middle of the twentieth century.
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3 years ago
A research submarine can withstand an external pressure of 62 megapascals (million pascals) all the while maintaining a comforta
Alex

Answer:

<em>The depth will be equal to</em> <em>6141.96 m</em>

<em></em>

Explanation:

pressure on the submarine P_{sea} = 62 MPa = 62 x 10^6 Pa

we also know that P_{sea} = ρgh

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g is acceleration due to gravity = 9.81 m/s^2

h is the depth below the water that this pressure acts

substituting values, we have

P_{sea} = 1029 x 9.81 x h = 10094.49h

The gauge pressure within the submarine P_{g} = 101 kPa =  101000 Pa

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Equating the pressure P_{sea}, we have

62 x 10^6 = 10094.49h

depth h = <em>6141.96 m</em>

7 0
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