Answer:
The tension in the cord is 24.1 Newton
Explanation:
<u>Step 1:</u> Data given
mass of the ball = 1.13 kg
Cord = 0.50m
velocity = 2.4 m/s
<u>Step 2:</u> Calculate the tension
Fnet = F(c)
T - F(g) = F(c)
⇒ with F(g) = force of gravity = m*g
⇒ with F(C) = centripetal force = (mv²)/r
T = (mv²)/r + mg
⇒ with m = mass = 1.133 kg
⇒ with v = velocity = 2.4 m/s
⇒ with r = radius = 0.50 m
T = (1.13 * 2.4²) / 0.50 + 1.13 * 9.81
T = 24.1 Newton
The tension in the cord is 24.1 Newton
Answer:
False
Explanation:
The force of an object does not depend on the dimensions of the said object. The formula for force is
F = Ma, where
m = mass and a = acceleration
The force is dependent on the size of the object and its acceleration. An object 2m by 5m running at a acceleration of x m/s² and weighing y kg will have the same force as another object 15m by 25m running at the same acceleration x m/s² and weighing y kg
Answer:
- 0.5 m/s²
Explanation:
m = mass of the clarinet case = 3.230 kg
W = weight of the clarinet case in downward direction
a = vertical acceleration of the case
Weight of the clarinet case is given as
W = mg
W = 3.230 x 9.8
W = 31.654 N
F = Upward force applied = 30.10 N
Force equation for the motion of the case is given as
F - W = ma
30.10 - 31.654 = 3.230 a
a = - 0.5 m/s²
Answer:
17.3 m
Explanation:
Given that,
Mass of a hammer is 0.58 kg
Velocity with which the hammer slides is 6.69 m/s at constant speed.
The roof makes an angle of 18 ◦ with the horizontal, and its lowest point is 18.2 m from the ground. We need to find the horizontal distance traveled by the hammer between the time is leaves the roof of the house and the time it hits the ground. Firstly, we will find the time taken by the hammer when it reaches ground in vertical direction.
Putting all the values,
Neglecting negative value,
To find horizontal distance, multiply 2.72 s with the horizontal component of velocity.
(a) 3000 V
For two parallel conducting plates, the potential difference between the plates is given by:
where
E is the magnitude of the electric field
d is the separation between the plates
Here we have:
is the electric field
d = 4.00 cm = 0.04 m is the distance between the plates
Substituting,
(b) 750 V
The potential difference between the two plates A and B is
Let's take plate A as the plate at 0 volts:
The potential increases linearly going from plate A (0 V) to plate B (3000 V).
So, if the potential difference between A and B, separated by 4 cm, is 3000 V, then the potential difference between A and a point located at 1 cm from A is given by the proportion:
and solving for V(1 cm) we find: