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Kryger [21]
3 years ago
13

If the temperature is held constant during this process and the final pressure is 671 torr , what is the volume of the bulb that

was originally filled with gas
Physics
1 answer:
MariettaO [177]3 years ago
4 0

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

Explanation:

From the question we are told that

   The initial pressure of the gas is  P_1 =  1.50 \  atm

   The volume of the second bulb is  V_2 =  0.800 \  L

   The  final pressure of the gas is  P_2 =  671 \ torr =  \frac{671 }{ 760}  =  0.883 \ atm

Let the unknown volume be represented as V_1 =  V \   L

Generally from Boyle's law we have that

      P_1 *  V_1 =  P_2 * V_2

=>   1.50 *  V =   0.883  * 0.800

=>   V  = 0.479 \ L

         

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Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016 Na+ ions arrive at the negative electrode and 3.
sladkih [1.3K]

Answer:

10.6 mA

Explanation:

t = time interval = 1.00 s

q = magnitude of charge on each ion = 1.6 x 10⁻¹⁹ C

n₁ = number of Na⁺ ions = 2.68 x 10¹⁶

q₁ = charge due to Na⁺ ions = n₁ q = (2.68 x 10¹⁶) (1.6 x 10⁻¹⁹) = 0.004288 C

n₂ = number of Cl⁻ ions = 3.92 x 10¹⁶

q₂ = charge due to Cl⁻ ions = n₂ q = (3.92 x 10¹⁶) (1.6 x 10⁻¹⁹) = 0.006272 C

i₁ = Current due to Na⁺ ions = \frac{q_{1}}{t} = \frac{0.004288}{1} = 0.004288 A

i₂ = Current due to Cl⁻ ions = \frac{q_{2}}{t} = \frac{0.006272}{1} = 0.006272 A

Current passing between the electrodes is given as

i = i₁ + i₂

i = 0.004288 + 0.006272

i = 0.01056 A

i = 10.6 x 10⁻³ A

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3 years ago
05. The time required to complete one lap around a perfectly circular track having a radius of 1,835 meters is 86
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Answer:

v = 134.06 m/s

Explanation:

Given that,

Radius of a circular track is 1,835 m

Time required to complete one lap around a perfectly circular track is 86 seconds

We need to find the car's velocity. Velocity is equal to,

v=d/t

On circular path,

v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 1835}{86}\\\\v=134.06\ m/s

So, car's velocity is 134.06 m/s.

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