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Kryger [21]
3 years ago
13

If the temperature is held constant during this process and the final pressure is 671 torr , what is the volume of the bulb that

was originally filled with gas
Physics
1 answer:
MariettaO [177]3 years ago
4 0

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

Explanation:

From the question we are told that

   The initial pressure of the gas is  P_1 =  1.50 \  atm

   The volume of the second bulb is  V_2 =  0.800 \  L

   The  final pressure of the gas is  P_2 =  671 \ torr =  \frac{671 }{ 760}  =  0.883 \ atm

Let the unknown volume be represented as V_1 =  V \   L

Generally from Boyle's law we have that

      P_1 *  V_1 =  P_2 * V_2

=>   1.50 *  V =   0.883  * 0.800

=>   V  = 0.479 \ L

         

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Which statement best describes the isothermal process? A. the temperature remains constant B. the temperature increases at a con
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a) Constant

b) Constant

Explanation:

a)

We can answer this question by using the equivalent of Newton's second law of motion of rotational motion, which can be written as:

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So we can rewrite eq.(1) as

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In this problem, we are told that at a given instant, the object has an angular acceleration due to the presence of torques, so there is a non-zero change in angular velocity.

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In this second case instead, all the torques are suddenly removed.

This also means that the net torque becomes zero as well:

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Therefore, this means that

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So also in this case, there is no change in angular velocity: this means that the angular velocity of the object will remain constant.

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