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DedPeter [7]
3 years ago
6

Evaluate the limit, or state that the limit does not exist 72 + 8

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0
The limit is 80 I think bc I added the numbers and uhm..yeah
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WILL MARK BRAINLIEST!!!!PLZ HELP!!!! An expression is shown below: 3pf2 − 21p2f + 6pf − 42p2 Part A: Rewrite the expression by f
Lesechka [4]

Answer:

See below.

Step-by-step explanation:

So, we have:

3pf^2-21p^2f+6pf-42p^2

PART A:

Find the GCF. Notice that we have a 3 in every term and a p in every term. Thus, the GCF is 3p:

3p(f^2-7pf+2f-14p)

This is the most we can do.

PART B:

Continue from where we left off. Factor the entire expression:

3p(f^2-7pf+2f-14p)\\3p(f(f-7p)+2(f-7p))\\3p((f+2)(f-7p))

7 0
2 years ago
What do you think the hypervolume of a hypercube is? Why?
gavmur [86]

Answer:

a^4 Where (a) is the side length of the hypercube

Step-by-step explanation:

A dimension can be simply defined as a direction in which matter can move it.

We live in a 3-dimensional world, matter can move in three basic directions. The formula for finding the volume of a cube is the following: (a^3). In the second dimension, a flat world, the area for the volume of a square is as follows: (a^2). However, a hypercube is a paradox, as it exists in 4-dimensions, thus it cannot exist in our world. However, scientists propose "String theory" which requires that matter can move in more directs than the (3) we know of in our world. In essence, there can be more than 3 dimensions. A hypercube is the 4-dimensional version of a cube. If it follows the area pattern that a square-object follows in all preceding dimensions then the area of a hypercube is (a^4).

Bear in mind that the area patter for a square-object is generally the following:

a^n

Where (a) is the side length of the square-object

(n) is the dimension the object is in.

Please keep in mind, this answer was written in the June of 2021, as science keeps progressing and new discoveries are made, this theory can be disproven. Therefore, this answer might be considered correct now, but it can be proven incorrect in the future.

6 0
2 years ago
I need help finding the answer
Daniel [21]
6x = n²-16
n²-6x-16=0             -16=-8*2,    -6=-8+2
(n-8)(n+2)=0
n-8=0,   n+2=0
n=8,      n=-2
Negative solution is -2.
5 0
3 years ago
What is the area of a triangle whose vertices are D(3, 3) , E(3, −1) , and F(−2, −5) ?
Jlenok [28]

The points given are: D=(3,3),E=(3,-1),F=(-2-5)

Area of the triangle is given by:

A = \frac{1}{2}| ( x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) )|

A = \frac{1}{2} |(3(-1+5) + 3(-5-3) -2(3+1))|

A = \frac{1}{2}|(3(4) + 3(-8) -2(4))|

A = \frac{1}{2} |( 12 -24 -8))|

A = \frac{1}{2} |( -20)|

A = |-10|

A = 10 \ units^2

6 0
3 years ago
I need this as soon as possible. Select all irrational numbers.
Phoenix [80]

A rational number can be expressed in the form

\frac{a}{b} where a and b are integers

Otherwise irrational

Note that \sqrt{8}, \sqrt{10}, \sqrt{2} are all irrational

\sqrt{}\frac{1}{16} = \frac{1}{4} → rational

\sqrt{}\frac{1}{8} → irrational

\sqrt{}\frac{1}{10} → irrational

\sqrt{}\frac{1}{4} = \frac{1}{2} → rational

\sqrt{}\frac{1}{2} → irrational





4 0
2 years ago
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