INDUCTION MOTOR:-
Speed:-Less speed range than PMAC motors • Speed range is a function of the drive being used — to 1,000:1 with an encoder, 120:1 under field-oriented control
Reliability:-Waste heat is capable of degrading insulation essential to motor operation • Years of service common with proper operation
Power density:-Induction produced by squirrel cage rotor inherently limits power density
Accuracy:-Flux vector and field-oriented control allows for some of accuracy of servos
Cost:-Relatively modest initial cost; higher operating costs
PERMANENT MAGNET MORTOR:-
speed:-VFD-driven PMAC motors can be used in nearly all induction-motor and some servo applications • Typical servomotor application speed — to 10,000 rpm — is out of PMAC motor range
Reliability:-Lower operating temperatures reduces wear and tear, maintenance • Extends bearing and insulation life • Robust construction for years of trouble-free operation in harsh environments.
power density:-Rare-earth permanent magnets produce more flux (and resultant torque) for their physical size than induction types.
Accuracy:-Without feedback, can be difficult to locate and position to the pinpoint accuracy of servomotors
<span>Cost:-Exhibit higher efficiency, so their energy use is smaller and full return on their initial purchase cost is realized more quickly</span>
(if it's frictionless the length doesn't even matter :) )
It would have the same kinetic energy down as the potential energy up. That is,

or

(the mass doesn't even matter). The result is

, so only the height matters really. It is almost 9 (it is

).
Answer:
given function is


formula for newton's method is

so derivative of function is

now put values and solve
or you can also use MATLAB code to solve
i.e
function p= newton(x)
e=0.001;
for i=1:100
if abs(d(x))>e
if abs(k(x))>0
xm=x-(k(x)/d(x));
x=xm;
else
end
break;
end
end
disp(x)
disp(k(x))
return;
Exothermic is the right kind of reaction.
Explanation:
Given that,
Area enclosed by a brass bracelet, 
Initial magnetic field, 
The electrical resistance around the circumference of the bracelet is, R = 0.02 ohms
Final magnetic field, 
Time, 
The expression for the induced emf is given by :
= magnetic flux
So, the induced emf in the bracelet is 0.678 volts.
Using ohm's law to find the induced current as :
V = IR


I = 33.9 A
or
I = 34 A
So, the induced current in the bracelet is 34 A. Hence, this is the required solution.