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pentagon [3]
4 years ago
11

1. A 2000kg truck at rest accelerates to 45m/s in 7 seconds. What is its change in kinetic energy?

Physics
1 answer:
Gemiola [76]4 years ago
5 0

Answer:

2025000 J

Explanation:

The formula for kinetic energy is KE=.5(m)(v²).  

The initial kinetic energy is 0 because it is at rest.  .5(m)(0) = 0.

To calculate the final kinetic energy, use the kinetic energy equation. KE = .5(2000)(45²) = 2025000 J.

To find the change in kinetic energy, you do KE(f) - KE(i).  2025000-0 = 2025000 J.

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Read 2 more answers
A 66.0 kg diver is 2.30 m above the water, falling at speed of 2.20 m/s. Calculate her kinetic energy as she hits the water. (Ne
fenix001 [56]

The kinetic energy of the diver as she hits the water is 159.72J. Details about kinetic energy can be found below.

<h3>How to calculate kinetic energy?</h3>

The kinetic energy of a body can be calculated using the following formula:

K.E = ½ × m × v²

Where;

  • K.E = kinetic energy
  • m = mass
  • v = velocity

According to this question, a 66.0 kg diver is 2.30 m above the water and falls at speed of 2.20 m/s.

Kinetic energy = ½ × 66 × 2.2²

K.E = 159.72J

Therefore, the kinetic energy of the diver as she hits the water is 159.72J.

Learn more about kinetic energy at: brainly.com/question/12669551

#SPJ1

6 0
2 years ago
Can someone help me fill in the two boxes.
puteri [66]

Answer:

Explanation:

I believe what you're looking for is :

Opposites

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Could be wrong but I think so.

7 0
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