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zhannawk [14.2K]
3 years ago
11

Why are group 1a (1) and group 2a (2) elements found in many compounds, but not group 8a (18) elements?

Chemistry
2 answers:
Inga [223]3 years ago
8 0

Explanation:

Generally, atoms of elements that have incomplete octet configurations are referred to as unstable and would readily involve themselves in reactions until they achieve their complete electronic configurations.

Group 1 and 2 elements happen to fall under that configuration. With these groups having 1 ( group 1 ) and 2 (group 2) electrons to lose in order to achieve their stable configuration, it is much feasible to lose those electrons in terms of energy and as such they are considered to be very reactivve as they would react with atoms of other elements. In the end, the goal is to have a configuration similar to that of the group 8a elements.

The group 8a elements on the other hand are termed as unreactive or stable because they already have a complete electronic configuration and as such there's no need to go into reactions with atoms of ther elements. This explains why there are very few group 8a elemements in compounds.

Rashid [163]3 years ago
4 0
Because group 1a and 2a are most reactive due to their least number of electrons in their outmost shell compared to group 8a(18)
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6 0
3 years ago
What is the pH of a solution that has a [H+] = 0.010 mol/L?
Serjik [45]

Answer:

pH = 2

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hope this helps :3

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5 0
2 years ago
A solution of water (kf=1.86 ∘c/m) and glucose freezes at − 2.15 ∘c. what is the molal concentration of glucose in this solution
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<span>1.16 moles/liter The equation for freezing point depression in an ideal solution is ΔTF = KF * b * i where ΔTF = depression in freezing point, defined as TF (pure) â’ TF (solution). So in this case ΔTF = 2.15 KF = cryoscopic constant of the solvent (given as 1.86 âc/m) b = molality of solute i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1. Solving for b, we get ΔTF = KF * b * i ΔTF/KF = b * i ΔTF/(KF*i) = b And substuting known values. ΔTF/(KF*i) = b 2.15âc/(1.86âc/m * 1) = b 2.15/(1.86 1/m) = b 1.155913978 m = b So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
7 0
3 years ago
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ANTONII [103]

The correct answer is:

b: Heluim

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Caffeine is a primary nervous system energizer of the methylxanthine class. It is the world's most universally consumed psychoactive drug. Unlike many other psychoactive elements, it is fair and unlimited in nearly all parts of the world. Caffeine can be arranged as an alkaloid, a term used for substances originated as end results of nitrogen metabolism in some plants.

5 0
3 years ago
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