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shepuryov [24]
3 years ago
5

What's is the mass of 0.500 mol NH3​

Chemistry
1 answer:
Setler [38]3 years ago
4 0

Answer:

8.5155g NH3

Explanation:

the molar mass of NH3​ is 17.031 g/mol

0.5 mol NH3 x 17.031 gNH3/1 mol NH3 = 8.5155g NH3

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Starting with lead (ii) carbonate describe how a solid sample of lead (ii) sulphate can be prepared
tatuchka [14]

The preparation of lead (ii) sulphate from lead (ii) carbonate occurs in two steps:

  1. insoluble lead carbonate is converted to soluble lead (ii) nitrate
  2. soluble lead (ii) nitrate is reacted with sulphuric acid to produce lead (ii) sulphate.

<h3>How can a  solid sample of lead (ii) sulphate be prepared from lead (ii) carbonate?</h3>

Lead (ii) carbonate and  lead (ii) sulphate are both insoluble salts of lead.

In order to prepare lead (ii) sulphate, a two step process is performed.

In the first step, Lead (ii) carbonate is reacted with dilute trioxonitrate (v) acid to produce lead (ii) nitrate.

  • PbCO₃ + 2HNO₃ → Pb(NO₃)₂ + CO₂ + H₂O

In the second step, dilute sulfuric acid is reacted with the lead (ii) nitrate to produce insoluble lead (ii) sulphate which is filtered and dried.

  • Pb(NO₃)₂ + H₂SO₄  →  PbSO₄ + 2HNO₃

In conclusion, lead (ii) sulphate is prepared in two steps.

Learn  more about lead (ii) sulphate at: brainly.com/question/188055

#SPJ1

4 0
2 years ago
Consider the following reaction where Kc = 1.80×10-2 at 698 K:2 HI (g) H2 (g) + I2 (g)A reaction mixture was found to contain 0.
Iteru [2.4K]

Answer:

Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F

Explanation:

At the given interval, concentration of HI = \frac{0.304}{1}M=0.304M

Concentration of H_{2} = \frac{5.07\times 10^{-2}}{1}M=5.07\times 10^{-2}M

Concentration of I_{2} = \frac{4.57\times 10^{-2}}{1}M=4.57\times 10^{-2}M

Reaction quotient,Q_{c} , for this reaction = \frac{[H_{2}][I_{2}]}{[HI]^{2}}

species inside third bracket represents concentrations at the given interval.

So, Q_{c}=\frac{(5.07\times 10^{-2})\times (4.57\times 10^{-2})}{(0.304)^{2}}=2.51\times 10^{-2}

So, the reaction is not at equilibrium.

As Q_{c}> K_{c} therefore reaction must run in reverse direction to reduce Q_{c} and make it equal to K_{c}. That means HI(g) must be produced and H_{2} must be consumed.

3 0
3 years ago
The half-life of radon-222 is 3.8 days. If a sample currently contains 3.1 grams of radon-222, how much radon-222 did this sampl
vodka [1.7K]

The   number  of grams of  radon 222 did it have 15.2  ago was  49.6 grams( answer  C)

 <u>calculation</u>

  • calculate the number of half life it has covered    from   15.2  days to 3.8 days

             that is  divide 15.2/ 3.8 = 4 half life

  •  half  life is time taken for a radio activity  of a specified isotope to fall to half its original mass

therefore  3.8 days ago  it was  3.1 x2 =  6.2 grams

                  7.6 days ago  it was 6.2 x2 = 12.4 grams

                   11.4  days  ago it was 12.4  x2=  24.8  grams

                  15.2  days  ago  it was  24.8 x2=49.6 grams





5 0
3 years ago
The function of this organelle is to create energy (ATP) through the process of cellular respiration.
dedylja [7]

Answer:

C

Explanation:

I hope this is correct and have a great day

3 0
3 years ago
Read 2 more answers
Which term names the concentration of salts dissolved in a liquid?
Viefleur [7K]
Hey there!
The answer is D, Salinity.
Salinity is the concentration of salt in water. Ocean water often has high salinity and this can contribute to things like upwelling and water density- but these all start from salinity.
Hope this helps!
4 0
3 years ago
Read 2 more answers
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