How can I balance this equation? ____ KClO3→ ____ KCl+ ____ O2
1 answer:
<span>the K and Cl are 1:1 .. the problem is in the O .. you have 3
(left side) and 2 (right side) .. you multiply the O2 on the right by 3 ..
KClO3 ---> KCl + 3 O2
and now you have 6 O on the right and 3 on the left .. so you multiply the KClO3 by 2 ..
2 KClO3 ---> KCl + 3 O2
now you have 6 O on both sides .. now balance the K and Cl by multiplying KCl on the right by 2 ..
2 KClO3 ---> 2 KCl + 3 O2</span><span>
</span>
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Answer
B i think
Explanation:
Answer:
Q = 87.31cal
Explanation:
Mass = 57.8g
T1 = 17.0°C
T2 = 43.5°C
Specific heat capacity (c) = 0.057cal/g°C
Q = MC∇T
Q = M*C*(T₂ - T₁)
Q = 57.8 * 0.057 * (43.5 - 17.0)
Q = 3.2946 * 26.5
Q = 87.306 cal
Q = 87.31cal
