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polet [3.4K]
3 years ago
10

Megan wants to see if mice that are fed food A or B grow at a faster rate. She measures the mass of the mice on day 1, then divi

des them into two groups based on the type of food they will be given. She feeds each group the same amount of food at the same time each day. Does Megan have a control group in this experiment?
Physics
2 answers:
diamong [38]3 years ago
7 0
<span>No, there is no control group because each group is treated under test conditions.</span>
Nat2105 [25]3 years ago
4 0

Answer:

No

Explanation:

It is an example of experimental group. Experimental group is defined as the group in an experiment under which each variable is tested, however, one variable is tested at a time.

On the other hand, control group is defined as the group which does not receive treatment by the researchers.

The only difference between the both group is that, under experimental group independent variable is changed but under control group it is held constant.

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A team of dogs accelerates a 290kg dogsled from 0 to 6.0m/s in 3.0 s. Assume that the acceleration is constant.Part AWhat is the
Mademuasel [1]

Answer:

(a) a=2m/sec^2

(b) 5220 j

(c) 1740 watt

(d) 3446.66 watt

Explanation:

We have given mass m = 290 kg

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Final velocity v = 6 m/sec

Time t = 3 sec

From first equation of motion

v = u+at

So a=\frac{v-u}{t}=\frac{6-0}{3}=2m/sec^2

(a) We know that force is given by

F = ma

So force will be F=290\times 2=580N

(b) From second equation of motion we know that

s=ut+\frac{1}{2}at^2=0\times 3+\frac{1}{2}\times 2\times 3^2=9m

We know that work done is given by

W = F s = 580×9 =5220 j

(c) Time is given as t = 3 sec

We know that power is given as

P=\frac{W}{t}=\frac{5220}{3}=1740Watt

(d) Time t = 1.5 sec

So P=\frac{W}{t}=\frac{5220}{1.5}=3466.66Watt

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