Answer:
the time taken for the object to fall is 6 s.
Explanation:
Given;
final velocity of the object, v = 58.8 m/s
initial velocity of the object, u = 0
The height of fall of the object is calculated as;
v² = u² + 2gh
v² = 2gh

The time to fall through the height is calculated as;

Therefore, the time taken for the object to fall is 6 s.
Answer:
As it moves farther and farther away from Q, it's speed will keep increasing.
Explanation:
This is so because the point charges are both positive charges and positive charges repel.
As the charges repel, they do so at an increasing speed.
Answer:
The relationship between diopter D and focal length f is D=1fD=1f So, f=−15.5=−0.182mf=−15.5=−0.182m
Explanation:
2s
Explanation:
Given parameters:
Current = 0.835A
Quantity of charge = 1.67C
Unknown:
Time taken = ?
Solution:
The quantity of electricity Q in coulombs is the product of the current I and time t.
Q = I x t
Q is the quantity of electricity in coulombs
I is the current
t is the time taken
input the values and solve for t;
1.67 = 0.835 x t
t =
= 2s
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Answer:
option (1)
Explanation:
fundamental frequency of open pipe, fopen = v/2L
fundamental frequency of closed pipe, f closed = v / 4L
By dividing both of them
f open = 2 x f closed
f open = two times f closed
f closed = 1 / 2 x f open