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polet [3.4K]
3 years ago
10

Megan wants to see if mice that are fed food A or B grow at a faster rate. She measures the mass of the mice on day 1, then divi

des them into two groups based on the type of food they will be given. She feeds each group the same amount of food at the same time each day. Does Megan have a control group in this experiment?
Physics
2 answers:
diamong [38]3 years ago
7 0
<span>No, there is no control group because each group is treated under test conditions.</span>
Nat2105 [25]3 years ago
4 0

Answer:

No

Explanation:

It is an example of experimental group. Experimental group is defined as the group in an experiment under which each variable is tested, however, one variable is tested at a time.

On the other hand, control group is defined as the group which does not receive treatment by the researchers.

The only difference between the both group is that, under experimental group independent variable is changed but under control group it is held constant.

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Meiosis produce
seraphim [82]
D)four cells that each have half as many chromosomes as the parent cell
7 0
4 years ago
Despite their name, standing waves actually do cause the medium to move
Gemiola [76]

Answer:

true

Explanation:

5 0
3 years ago
If the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave?
GaryK [48]

Answer:

f = 614.28 Hz

Explanation:

Given that, the length of the air column in the test tube is 14.0 cm. It can be assumed that the speed of sound in air is 344 m/s. The test tube is a kind of tube which has a closed end. The frequency in of standing wave in a closed end tube is given by :

f=\dfrac{nv}{4l}

f=\dfrac{1\times 344}{4\times 0.14}

f = 614.28 Hz

So, the frequency of the this standing wave is 614.28 Hz. Hence, this is the required solution.

4 0
4 years ago
Joe and Jim start at rest at the starting line of a race track. Both runners accelerate at the same rate, but Joe accelerates fo
eduard

Answer:

Vf₂ = 2 Vf₁

It shows that final speed of Joe is twice the final speed of Jim.

Explanation:

First, we analyze the final speed of Jim by using first equation of motion:

Vf₁ = Vi + at

where,

Vf₁ = final speed of Jim

Vi = initial speed of Jim = 0 m/s

a = acceleration of Jim

t = time of acceleration for Jim

Therefore,

Vf₁ = at   ---------------- equation (1)

Now, we see the final speed of Joe. For Joe the parameters will become:

Vf = Vf₂

Vi = 0 m/s

a = a

t = 2t

Therefore,

Vf₂ = 2at  

using equation (1):

<u>Vf₂ = 2 Vf₁</u>

<u>It shows that final speed of Joe is twice the final speed of Jim.</u>

3 0
3 years ago
During a race, a runner runs at a speed of 6 m/s. Four seconds later, she is running at a speed of 10 m/s. what is the runners a
Georgia [21]
<span>a = (v2 - v1)/t = (10 - 6)/2 = 2 m/sec/sec (average acceleration)</span>
8 0
4 years ago
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