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shusha [124]
3 years ago
15

jamal wanted only to test the effect of the free fall and so he put his system in a vacuum to prevent air resistance. In free fa

ll, will the crumpled or flat paper reach the ground first?
Physics
2 answers:
Elis [28]3 years ago
8 0

Explanation :

It is given that, Jamal wanted only to test the effect of the free fall and so he put his system in a vacuum to prevent air resistance.

Vacuum is also called as free space. In a vacuum there is no air resistance. We know that the air resistance depends on surface area.

But in the vacuum there is is no resistive force. So, in free fall both crumpled or flat paper will reach the ground at the same time.

Alborosie3 years ago
6 0

Both papers will reach the ground at the same time. CORRECT ANSWER

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Find the density of seawater at a depth where the pressure is 680 atm if the density at the surface is 1030 kg/m3. Seawater has
Pie

Answer:

1060.41kg/m^3

Explanation:

Bulk modulus is defined as the relative change in the volume of a body produced by a unit of compressive acting uniformly over its surface:

B=\rho _o \frac{\bigtriangleup P }{\bigtriangleup \rho}

Hence the density of the seawater at a depth of 680atm is calculated as:-

\rho=\rho_o +\bigtriangleup \rho=\rho_o(1+\frac{\bigtriangleup P}{B})\\\\=1030 \times (1+ \frac{(680-1)\times10^5}{2.3\times 10^9})\\=1060.41kg/m^3

4 0
3 years ago
Which term is defined as a change in an object's position relative to a reference point?
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The answer would be REFERENCE POINT
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3 years ago
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A roller of radius 12.5 cm turns at 14 revolutions per second. What is the linear velocity of the roller in meters per second?
Firdavs [7]

12.5 times 14 and convert to meters its 1.75 meters per second

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3 years ago
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In a television set, electrons are accelerated from rest through a potential difference of 20 kV. The electrons then pass throug
Svetradugi [14.3K]

Answer: Fmax = 5.54*10^-12 N

Explanation: From the question, we have the potential difference (V) =20kv = 20,000v and strength of magnetic field (B) =0.41 T.

The maximum force experienced by a charge of magnitude (q) is given as

Fmax = qvB

Where v = velocity of electron.

The velocity of the electron can be gotten by using the work energy theorem.

The kinetic energy of the electron (mv²/2) equals the work done needed to accelerate it.

mv²/2 = qV.

Where m = mass of an electronic charge = 9.11×10^-31 kg, q = magnitude of an electronic charge = 1.609×10^-19 c, v = velocity of electron, V = potential difference = 20,000v.

By substituting the parameters, we have that

(9.11×10^-31 × v²)/2 = 1.609×10^-19 × 20000

(9.11×10^-31 × v²) = 1.609×10^-19 × 20000 ×2

v² = (1.609×10^-19 × 20000 ×2)/9.11×10^-31

v² = 64.36*10^(-16)/9.11×10^-31

v² = 7.0647×10^15

v = √7.0647×10^15

v = 8.40×10^7 m/s

Fmax = 1.609×10^-19 × 8.40×10^7 × 0.41

Fmax = 5.54*10^-12 N

7 0
3 years ago
You want to move a 4- kg bookcase to a different place in the living room. If u push with a force of 65 n and the bookcase accel
IrinaK [193]

Answer:

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The equation of the forces along the horizontal direction is:

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a=0.12 m/s^2 is the acceleration

The force of friction can be written as F_f = \mu R (2), where

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R-mg=0 (3)

since the bookcase is in equilibrium. Substituting (2) and (3) into (1), we find

F-\mu mg = ma

And solving for \mu,

\mu = \frac{F-ma}{mg}=\frac{65-(4)(0.12)}{4(9.8)}=1.65

7 0
3 years ago
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