Answer:
x component 3.88 y- component 14.488
Explanation:
We have given a vector A which has a magnitude of 15 m/sec which is at 75° counter-clock wise ( anti-clock wise) from x -axis which is clearly shown in bellow figure
Now x-component will be 15 cos75°=3.8822 ( as it makes an angle of 75° with x-axis )
y- component will be 15 sin 75°=14.488
For verification the resultant of x and y component should be equal to 15
So 
The frictional force will be 0.22N.
<h3>What is Frictional force?</h3>
Frictional force is the force generated between two surfaces that are in contact and slide against each other.
Given,
Weight=4N
mass =4.9/9.8=0.5kg
Hieght =30m
velocity=24m/s
Acceration , v²-u²=2as
24²/2×30 =a , u is zero
a= 1.5m/s²
By Using conservation of energy ,
30F+1/2mv²=mgh
30F=1150-144
F= 6/30
F=0.2N
The force will be 0.2N
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The government should put it support in a combination of sources, as no
source in the present can fully provide all energy requirements.
Answer:
145 m
Explanation:
Given:
Wavelength (λ) = 2.9 m
we know,
c = f × λ
where,
c = speed of light ; 3.0 x 10⁸ m/s
f = frequency
thus,

substituting the values in the equation we get,

f = 1.03 x 10⁸Hz
Now,
The time period (T) = 
or
T =
= 9.6 x 10⁻⁹ seconds
thus,
the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s
Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s
Now,
For radar to detect the object the pulse must hit the object and come back to the detector.
Hence, the shortest distance will be half the distance travelled by the pulse back and forth.
Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}
Thus, the minimum distance to target =
= 145 m