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liq [111]
3 years ago
7

A tennis player player receives a shot with the ball (.06kg) travelling horizontally at 50.0 m/s and returns the shot with the b

all travelling horizontally at 40.0 m/s in the opposite direction. a) What is the impulse delivered to the ball by the tennis racquet? b) What work does the racquet do on the ball?
Physics
1 answer:
ahrayia [7]3 years ago
3 0
Let: 

<span>m- 0.0600Kg </span>
<span>v1- +50.0 m/s </span>
<span>v2- -42 m/s </span>

<span>a) </span>

<span>momentum1 - momentum2 = impulse </span>
<span>p1 - p2 = Ft </span>
<span>m(v1 + v2) = Ft </span>
<span>Ft = 0.54 N-s </span>

<span>b) </span>

<span>Work is traditionally force times distance but an easy way to get through this one is to think logically and keep your units straight: </span>

<span>The racket creates an overall velocity of 90 m/s for the ball: </span>

<span>W=(Ft)*(V) </span>
<span>W=0.54 N-s * 90 m/s </span>
<span>W=48.6 N-m = 48.6 J</span>
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