Answer:
B. space quantization.
Explanation:
In 1921, Otto Stern developed the idea behind this experiment, while Walther Gerlach performed the actual experiment in 1922. The Ster-Gerlach experiment provides prove to the fact that the spatial orientation of angular momentum is quantized. To demonstrate the experiment, silver atoms were made to travel through a magnetic field path.
Before they hit the screen(usually a glass slide), they were deflected because of their non-zero magnetic moment. There was an expected result for this experiment, but the actual observation on the glass slide was a continuous distribution of the silver atoms that actually hit the glass. This experiment was useful in proving that in all atomic-scale systems, there was a quantization of angular momentum.
B damage the protective layers of the artery walls, which can intimately lead to heart disease.
Answer:
-0.9045 j
Explanation:
Here K= 270 N/m
distance 1 = 4.60 mm=0.0046 m
when pen is compressed ;
distance 2 = 6.70 mm + distance1 = 0.0067 m+0.0046 m= 0.0113 m
The pen store in itself two types of PE
Which is Initial PEi = 1/2 ×K× [
=0.5×270×0.0046 =0.621 j
and Final PEf = 1/2 × K ×
= 0.5×270×0.0113=1.5255 j
When the pen gets ready - it goes ahead distance d2 and is then pressed back distance d1 for writing.
Total PE when ready = 0.621-1.5255= - 0.9045 j
so, work = -0.9045 j
Answer:
<em><u>Hypothesis #2 If an earthworm is exposed to a strong odor, then it will back away from the odor because it will think that the odor is a sign of danger. ... Second, you will test earthworms' response to dry conditions by providing both a dry surface and a moist surface for the earthworms to crawl on.</u></em>
Answer:
The current in the coil is 60 Ampere.
Explanation:
Given:
Number of turns in the coil is N = 25
Dimension of the coil = 15cm X 12cm
magnitude of magnetic field = 0.20T
angle in the xy plane is θ = 0 degree
torque τ = 5.4 N-m
To find:
current in the coil is i = ?
Solution:
The torque acting on the coil is given by
=> 
Converting cm to m
12 cm = 0.12 m
15 cm = 0.15 m
The area of the coil is
A = 0.12 X 0.15
A = 
Substituting the values
=>
=>
=>
=>
=>
=>
=> i = 60 A