Q = 5637 J
C =4.814 J/KgºC
Temperature : 45.5ºC - 20.9º C = 24.6ºC
Q = m x C x T
5637 = m x 4.814 x 24.6
5637 = m x 118.4244
m = 5637 / 118.4244
m = 47.60 g
hope this helps!
Left side metals right side non metals. arrganged in groups (columns) and periods (rows), each group tells you amount of valence electrons
I believe its A. please correct me if im wrong! <3
Seen in the electrons, which are found in the atomic cloud surrounding the nucleus.
Note: We must keep the units we use consistent. The Cp is given in cal/gC so we will use cal for energy, grams for mass and C for temperature.
1)
Heat supplied can be calculated using:
Q = mCpΔT; where m is the mass, Cp is the specific heat capacity and ΔT is the temperature change.
Q = 367 x 0.092 x (60 - 23)
Q = 125 Cal
2)
Using the same equation:
125 = 60 x 0.092 x (T - 23)
T = 45.6 C
