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3 years ago

6

A 50 kg wagon is pulled with a 100 N force. If the force is increased to 200 N, how quickly will the wagon accelerate? 1 m/s2 2

m/s2 4 m/s2 25 m/s2

2 answers:

motikmotik3 years ago

6 0

Answer:

4 m per second

Explanation:

Katen [24]3 years ago

3 0

4 m/s2

I hope this helps!

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Brainliest and 100 POINTS

anastassius [24]

Reflection- serious thought or consideration

Absorption- the process or action by which one thing absorbs or is absorbed by another.

Diffusion- the spreading of something more widely.

Diffraction- the process by which a beam of light or other system of waves is spread out as a result of passing through a narrow aperture or across an edge, typically accompanied by interference between the wave forms produced.

Refraction- measurement of the focusing characteristics of an eye or eyes

8 0

3 years ago

Read 2 more answers

A series circuit has four resistors. The current through one resistor is 810 mA. How much current is supplied by the source?0.81

Papessa [141]

Answer:

810 mA

Explanation:

In a series circuit, the current is the same through the system, so if the current through one resistor is 810 mA, the current supplied by the source will be 810 mA.

So, the answer is 810 mA

8 0

1 year ago

Pls answer this

igor_vitrenko [27]

Answer:

37.8225 J

Explanation:

kinetic energy = 1/2 of mass x $velocity^{2}$

6 0

3 years ago

Please answer ASAP, and please don't joke around and actually do answer my question. I will give you brainliest if you answer it

hammer [34]

Answer:

30 feet

Explanation:

First off, if they are throwing at 12.0 m/s and it takes 2.5 seconds. It will be the act of multiplication.

12 times 2.5 is 30, because 12 times 2 is 24 plus 12 divided by 2 which is 6 so 24 plus 6 is 30.

8 0

3 years ago

Calculate the true mass (in vacuum) of a piece of aluminum whose apparent mass is 4.5000 kgkg when weighed in air. The density o

spin [16.1K]

Answer:

The true weight of the aluminium is $m_{alu} =$ 4.5021 kg

Explanation:

Given data

$m_{app}$ = 4.5 kg

$\rho_{air}$ = 1.29 $\frac{kg}{m^{3} }$

$\rho_{al}$ = 2.7× $10^{3} \frac{kg}{m^{3} }$

The true mass of the aluminium is given by

$m_{alu} = \frac{\rho_{alu}m_{app}}{\rho_{alu} -\rho_{air} }$

Put all the values in above equation we get

$m_{alu} = \frac{(2700)(4.5)}{2700-1.29}$

$m_{alu} =$ 4.5021 kg

Therefore the true weight of the aluminium is $m_{alu} =$ 4.5021 kg

6 0

3 years ago