Explanation:
Let f₁ is the fundamental frequency, 
Lower pitch frequency, 
Fundamental frequency is, 
.....(1)
Lower frequency is, 
..............(2)
Dividing equation (1) and (2) as :
So, the ratio of linear mass density μ of the string with the higher pitch to that of the string with the lower pitch is 0.00132. Hence, this is the required solution.
Answer:
6 m/s
Explanation:
p=mv
p=3 kg.m/s
m=0.5 kg
rearrange and substitute to find v:
(3)=(0.5)v
v=3/0.5
v=6 m/s
FORCES HAVE STRENGTH AND DIRECTION
Answer:
When an unbalanced force acts on a body the side with the greater force's dircetion makes the object move along its direction
Also to find the net force acting on the bofldy you can subtract the two force acting on the body
In case of balanced force the net force will always be 0
Answer:
96%
Explanation
Let A the total area of the galaxy, is modeled as a disc:
A = πR^2 = π (25 kpc)^2
And let a be the area that astronomers are able to see:
a = πr^2 = π(5 kpc)^2
The percentage that can be seen is equal to 100 times the ratio of the areas, of the galaxy and the "visible" part:
P = 100 a/A = (5/25)^2 = 100/25 = 4%
Therefore, the percentage of the galaxy not included, i.e. not seen is:
(100-4)% = 96%
