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iVinArrow [24]
4 years ago
11

Observations show that the dragonflies complete one revolution every 0.017 s during this "spin dry" maneuver. What is their angu

lar speed in radians per second?
Physics
1 answer:
polet [3.4K]4 years ago
7 0

Answer:

\omega=369.6\frac{rad}{s}

Explanation:

The time taken to complete one revolution is the period and is defined as:

T=\frac{1}{f}(1)

The angular speed is given by:

\omega=2\pi f\\f=\frac{\omega}{2\pi}(2)

Replacing (2) in (1) and solving for \omega:

T=\frac{1}{\frac{\omega}{2\pi}}\\\omega=\frac{2\pi}{T}\\\omega=\frac{2\pi}{0.017s}\\\omega=369.6\frac{rad}{s}

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A spaceship ferrying workers to moon Base i takes a straight-line pat from the earth to the moon, a distance of 384,000km, Suppo
GrogVix [38]

Answer:

95.78125%

18000 m/s

22233.33 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow v=0+20\times 15\times 60\\\Rightarrow v=18000\ m/s

The velocity of the rocket at the end of the first 15 minutes is 18000 m/s which is the maximum speed of the rocket in the complete journey.

Distance traveled while speeding up

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 20\times 900^2\\\Rightarrow s=8100000\ m

Distance traveled while slowing down

s=18000\times 900+\dfrac{1}{2}\times -20\times 900^2\\\Rightarrow s=8100000\ m

Distance traveled during constant speed

384000000-(2\times 8100000)=367800000\ m

Fraction

\dfrac{367800000}{384000000}\times 100=95.78125\ \%

Fraction of the total distance is traveled at constant speed is 95.78125%

Time taken at constant speed

t=\dfrac{367800000}{18000}=20433.33\ s

Total time taken is 900+20433.33+900=22233.33\ s

6 0
3 years ago
As the speed/velocity of an object increases what happens to the kinetic energy of the object
Elanso [62]
The kinetic energy increases
8 0
3 years ago
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A topic list is a list of important content and material which will be covered on a test.   Please select the best answer from t
Iteru [2.4K]
Sounds T to me. My teacher used to give those out.
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3 years ago
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A 0.50 kg object is at rest. A 2.88 N force to the right acts on the object during a time interval of 1.48 s. a) What is the vel
Murljashka [212]

Answer:

8.5m/s

Explanation:

We are given that

Mass of object=m=0.50 kg

Initial velocity, u=0

Force=F=2.88 N

Time=1.48 s

a.We know that

F=ma

Using the formula

2.88=0.50a

a=\frac{2.88}{0.50}=5.76m/s^2

a=\frac{v-u}{t}

Using the formula

5.76=\frac{v-0}{1.48}

v=5.76\times 1.48=8.5m/s

Hence, the velocity of the object at the end of this time interval=8.5m/s

8 0
3 years ago
A professional boxer hits his opponent with a 1035 N horizontal blow that lasts 0.175 s. The opponent's total body mass is 120 k
12345 [234]

Answer:

(a) vf = 1.51 m/s

(b) vf = 36.22 m/s

Explanation:

The rate of change of momentum is equal to the force:

F = \frac{mv_f-mv_i}{t}

Ft = m(v_f-v_i)

where,

F = Force = 1035 N

t = time = 0.175 s

vi = initial speed = 0 m /s

vf = final speed = ?

(a)

m = mass of body = 120 kg

Therefore,

(1035\ N)(0.175\ s)=(120\ kg)(v_f - 0\ m/s)\\\\v_f = \frac{181.125\ Ns}{120\ kg} \\\\

<u>vf = 1.51 m/s</u>

<u></u>

(b)

m = mass of head = 5 kg

Therefore,

(1035\ N)(0.175\ s)=(5\ kg)(v_f - 0\ m/s)\\\\v_f = \frac{181.125\ Ns}{5\ kg} \\\\

<u>vf = 36.22 m/s</u>

7 0
4 years ago
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