<h2>
Velocity of rock when it hits the ground is -64 ft/s</h2>
Explanation:
Its position function is s(t) = –16t² + 64t
When it reaches back ground s(t) = 0 ft
Substituting
s(t) = –16t² + 64t = 0
t² - 4t = 0
t² = 4t
t =4 seconds
Now we need to find velocity when it reaches ground, that is velocity after 4 seconds.
Differentiating s(t) equation
v(t) = -32t+64
Substituting t = 4 seconds
v(4) = -32 x 4+64 = -64 ft/s
Velocity of rock when it hits the ground is -64 ft/s
Answer:
The ability of our bodies to adapt to different levels of gravity. You would become weaker and your heart is use to zero gravity. Boredom because there isn't much to in space. When intelligent people get bored, it's not pretty all the time...
You could heat the syrup, grease the spoon with shortening, because if you do, then the molasses won't stick when you pour it out of the spoon into the batter.
Since the position doesn't change over that time, it's zero
