Answer:
6He = 4.90 MeV/Nucleon
8Li = 5.18 MeV / Nucleon
62Ni = 8.82 MeV / Nucleon
115 In = 8.54 MeV / Nucleon
Explanation:
Our strategy here is to remember that when the mass of a given nuclei is calculated from the sum of the mass of its protons and neutrons, this mass is greater than the actual value . This is the mass defect.
Now this mass defect we can convert to energy by utilizing Einstein´s equation, E = mc².This is the binding energy.
For 6He with actual mass 6.0189 u ( He has Z = 2, that is 2 protons )
mass protons = 2 x 1.0078 u = 2.0516 u
mass neutrons = 4 x 1.0087 u = 4.0348 u
predicted mass = (2.0516 + 4.0348) u = 6.0504 u
mass defect = (6.0504 - 6.0189) u = 0.0315 u
Now we need to convert this mass expressed in atomic mass units to kilograms ( 1 u = 1.66054 x 10⁻²⁷ Kg )
0.0315 u x 1.66054 x 10⁻²⁷ Kg =5.231 x 10⁻²⁹ Kg
E =5.231x 10⁻²⁸ Kg x (3 x 10⁸ m/s )² = 4.707 x 10⁻¹²J
Finally we will convert this energy in Joules to eV
E = 4.707 x 10⁻¹² J x 6.242 x 10¹⁸ eV/J = 2.94 x 10⁷ eV = 29.4 MeV
E per nucleon for 6He = 29.4 MeV / 6 =4.90 MeV / Nucleon
Now the calculations for the rest of the nuclei are performed in similar manner with the following results:
8Li = 5.18 MeV / Nucleon
62Ni = 8.82 MeV / Nucleon
115 In = 8.54 MeV / Nucleon
