All categories

2 years ago

What is baking soda chemically known as ? Excessive use of chemical

Chemistry

2 answers:

andreyandreev [35.5K]2 years ago

7 0

Answer:

Baking Soda is NaHCO3 ---Sodium hydrogen Carbonate

Excessive use of Fertilizer can cause plants to develop shallow root systems,Decrease soil fertility and reduce Quality of Crops.

My name is Ann [436]2 years ago

4 0

Answer:

Sodium bicarbonate, also called sodium hydrogen carbonate, or bicarbonate of soda, is a source of carbon dioxide and so is used as an ingredient in baking powders, in effervescent salts and beverages, and as the main constituent of dry-chemical fire extinguishers.

Explanation:

You might be interested in

What volume would 0.853 moles of Nitrogen gas occupy at STP?

beks73 [17]

Answer:

19.12 L

Explanation:

At STP(i.e. Standard temperature and pressure).

The volume occupied by one mole of gas = 22.4 L

The pressure = 1 atm

The temperature = 273 K

Thus, since 1 mole of gas = 22.4 L;

Then 0.853 moles of N2 gas will occupy:

= (0.853 moles of N2 gas × 22.4 L)/ 1 mole of N2 gas

= 19.12 L

6 0

3 years ago

A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor

AlexFokin [52]

Answer : The partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of $C_2HBrClF_3$ = 15.0 g

Mass of $O_2$ = 22.6 g

Molar mass of $C_2HBrClF_3$ = 197.4 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_2HBrClF_3$ and $O_2$ .

$\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole$

and,

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole$

Now we have to calculate the mole fraction of $C_2HBrClF_3$ and $O_2$ .

$\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971$

and,

$\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903$

Now we have to partial pressure of $C_2HBrClF_3$ and $O_2$ .

According to the Raoult's law,

$p^o=X\times p_T$

where,

$p^o$ = partial pressure of gas

$p_T$ = total pressure of gas

$X$ = mole fraction of gas

$p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T$

$p_{C_2HBrClF_3}=0.0971\times 862torr=84torr$

and,

$p_{O_2}=X_{O_2}\times p_T$

$p_{O_2}=0.903\times 862torr=778torr$

Therefore, the partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

6 0

2 years ago

ASAP PLEASE HELP ASAP

Salsk061 [2.6K]

swift to hear, slow to speak

Explanation:

7 0

2 years ago

which of the following would a chemist be most likely to study? a. a leaf floating on water c. a leaf being blown by the wind b.

Salsk061 [2.6K]

I think the correct answer from the choices listed above is option B. It would be a leaf changing color in autumn <span>would a chemist be most likely to study. A chemist should be more interested in processes that chemical reactions are most likely to occur and changes in color can be one of the indications of such reactions.</span>

6 0

2 years ago

Is the bond type of PCl3 polar or nonpolar?

Maru [420]

The molecular polarity and bond type of PCl3 is polar.

6 0

2 years ago