A 12.5-g marble display 5.0 mL of water. What is its density?
2 answers:
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<u>Answer:</u> The heat required will be 58.604 kJ.
<u>Explanation: </u>
To calculate the amount of heat required, we use the formula:
Q= heat gained or absorbed = ? J
m = mass of the substance = 100 g
c = heat capacity of water = 4.186 J/g ° C
Putting values in above equation, we get:
Q = 58604 Joules = 58.604 kJ (Conversion factor: 1 kJ = 1000J)
Thus, heat released by 100 grams of ice is 58.604kJ.