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kicyunya [14]
2 years ago
6

A 12.5-g marble display 5.0 mL of water. What is its density?

Chemistry
2 answers:
Irina-Kira [14]2 years ago
8 0
In g/mL, 12.5/5, so 2.5 g/mL
anastassius [24]2 years ago
5 0
12.5 g/ 5.0 mL= 2.5 g/L

The final answer is 2.5 g/L~
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Explanation:

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Relation between entropy and microstate is as follows.

           S = K_{b} \times ln \Omega

where,      S = entropy

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This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that \Omega = 1, and \Omega' = 0.833

Therefore, change in entropy will be calculated as follows.

     \Delta S = K_{b} \times ln \Omega' - K_{b} \times ln \Omega

                 = 1.38 \times 10^{-23} \times ln(0.833) - 1.38 \times 10^{-23} \times \times ln(1)

                 = 1.38 \times 10^{-23} \times (-0.182)

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or,             = -2.51 \times 10^{-24}

Thus, we can conclude that the entropy change for a particle in the given system is -2.51 \times 10^{-24} J/K particle.

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3 years ago
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Explanation:

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An unknown element is shiny and is found to be a good conductor of electricity, what other properties would you predict for it
VLD [36.1K]
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hope it helps.

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