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kicyunya [14]
3 years ago
6

A 12.5-g marble display 5.0 mL of water. What is its density?

Chemistry
2 answers:
Irina-Kira [14]3 years ago
8 0
In g/mL, 12.5/5, so 2.5 g/mL
anastassius [24]3 years ago
5 0
12.5 g/ 5.0 mL= 2.5 g/L

The final answer is 2.5 g/L~
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To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

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\frac{P_1}{T_1}=\frac{P_2}{T_2}

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\frac{149}{259}=\frac{P_2}{290.3}\\\\P_2=167kPa

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