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3 years ago

According to the periodic table carbon has a tendency to bond covalently with

Chemistry

2 answers:

blondinia [14]3 years ago

5 0

Answer:

Carbon tends to bond covalently with Hydrogen

lisov135 [29]3 years ago

3 0

Answer:

All the carbon group atoms, having four valence electrons, form covalent bonds with nonmetal atoms; carbon and silicon cannot lose or gain electrons to form free ions, whereas germanium, tin, and lead do form metallic ions but only with two positive charges.

Explanation:

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Use the image to answer the question.

liberstina [14]

Answer:b

Explanation: it’s in the picture just go counterclockwise

7 0

3 years ago

Read 2 more answers

Explain how you were able to use your knowledge of how different types of blood react with anti A, anti B, and anti Rh antibodie

dybincka [34]

Depending upon the clumping reaction with anti A , anti B and anti Rh antibodies the blood types are determined.

Explanation:

Agglutination (clumping) will occur when blood that contains the particular antigen is mixed with the particular antibody.

A+ have Agglutination with Anti-A ,Anti-Rh and No agglutination with Anti-B.

A- have Agglutination with Anti-A and No agglutination with Anti-B and Anti-Rh.

B+ have Agglutination with Anti-B Anti-Rh and No agglutination with Anti-A.

B- have Agglutination with Anti-B and No agglutination with Anti-B and Anti-Rh.

Rh+ have Agglutination with Anti-A and Anti-Rh and No agglutination with Anti-B.

Rh- have No Agglutination with Anti-A and Anti-B and Anti-Rh.

3 0

3 years ago

Given the equations below, what is the heat of reaction for the process in which carbon monoxide is formed from its elements?

murzikaleks [220]

The answer is B, -110.5.

7 0

3 years ago

Read 2 more answers

Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline.

lesya692 [45]

Answer:

$n_{CO_2}=1.93 gCO_2$

Explanation:

Hello,

In this case, considering the given chemical reaction, we can use the molar mass of octane (114.23 g/mol) and the 2:16 molar ratio with carbon dioxide to compute the emitted moles of CO2 to the atmosphere via the following stoichiometric procedure:

$n_{CO2}=27.6gC_8H_{18}*\frac{1molC_8H_{18}}{114.23gC_8H_{18}} *\frac{16molCO_2}{2molC_8H_{18}} \\\\n_{CO_2}=1.93 gCO_2$

Which also corresponds to the following mass:

$m_{CO_2}=1.93molCO_2*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=85.0gCO_2$

Best regards.

6 0

3 years ago

The solid XY decomposes into gaseous X and Y: XY(s) m X(g) + Y(g) Kp = 4.1 (at 0 °C) If the reaction is carried out in a 22.4 L

tia_tia [17]

Answer:

None of the conditions will favor either the forward reaction or backward reaction , hence the answer is D

Explanation:

The principle of chemical Equilibrium is applied here, where the concentration of the reactants or the forward reaction is same as the concentration of the products or the backward reaction.

The equilibrium constants is also involved here, K can be in terms of pressure (Kp) or concentration (Kc) hence equilibrium constant is the ration of the concentration of the products to the concentration of the reactants raised to the power of the coefficient of the reactants and products.
Partial pressure , total pressure and the mole fraction relationship is also applied
The step by step explanation is as shown in the attachment below.

4 0

3 years ago