Answer:
The youth hockey training facility
Explanation:
Answer:
C is the correct answer coz the others don't make sense
Answer:
Uair = 0.0749 KW/k = 74.9 W/k
Explanation:
The natural air change per hour is given by the formula:
Natural Air Change per Hour = ACPH = 60*Volume Flow/Volume
where,
ACPH = 0.4
Volume Flow = ? in ft³/min
Volume = 19456 ft³
Therefore,
0.4 = (60 min)(Volume Flow)/(19456 ft³)
Volume Flow = (0.4)(19456 ft³)/(60 min) = (129.7 ft³/min)(1 min/60 s)
Volume Flow = (2.16 ft³/s)(0.3048 m/1 ft)³ = 0.061 m³/s
Now, we find heat loss coefficient:
Uair = Volumetric Flow*Density of air*Specific Heat Capacity of air
Uair = (0.061 m³/s)(1.225 kg/m³)(1 KJ/kg.k)
<u>Uair = 0.0749 KW/k = 74.9 W/k</u>
Answer:
I’m sorry I don’t understand this is there more steps?♀️
Explanation:
