Answer:
Hello there, please check step by step explanations to get answers.
Explanation:
Given that:
5-hp single-cylinder engine is used. At most, the belt transmits 60 percent of this power. The driving sheave has a diameter of 6.2 in. and the driven, 12.0 in. The belt selected should be as close to 92 in pitch length as possible. The engine speed is governor-controlled to a maximum of 3100 rev/min. Select a satisfactory belt, and specify it using the standard designation.
See attached documents for clearity and step by step procedure to answer
Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
Answer:
Detailed solution is attached below in three simple steps the problem is solved.
Answer:
the time, in hours = 4.07hrs
Explanation:
The detailed step by step derivation and appropriate integration is as shown in the attached files.
Answer: So a 1 pound = 0.453592kg
the density of the water is D= 997 kg/
so we need to use replace the kg with pounds with 2.20462 pounds = 1kg.
then D = 2.20462*997 pounds/
and we want to make this equal to one changing the metters for other thing.
we need to replace 
with 2.020462*997 meters qube.
then our new metters variable x = 12.6meters.
now g = 9.8 meters for second square.
in our new lenght variable x.
g = 12.6*9.8 x for second square.
so if y is our new time variable
= 12.6*9.8 seconds square. so y = 11.1seconds
so the units of length are x = 12.6 meters and for time y = 11.1 seconds.
